What is the relationship between refractive index and pressure in gases?

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SUMMARY

The refractive index of a gas, denoted as n_r, is directly related to pressure through the equation n_r = 1 + K × p, where K is a constant that needs to be determined. The Clausius-Mossotti equation is relevant in this context, linking the refractive index to the gas's density and molecular properties. The ideal gas law, expressed as ρ = mp/(nRT), plays a crucial role in understanding how density varies with pressure, which in turn affects the refractive index. This relationship is essential for solving problems related to gas optics and pressure variations.

PREREQUISITES
  • Understanding of the ideal gas law and its implications on density
  • Familiarity with the Clausius-Mossotti equation
  • Basic knowledge of refractive index concepts
  • Mathematical skills for manipulating equations
NEXT STEPS
  • Research the derivation of the Clausius-Mossotti equation
  • Explore the relationship between density and pressure in gases using the ideal gas law
  • Investigate how changes in pressure affect the refractive index in various gases
  • Learn about the applications of refractive index in optical systems
USEFUL FOR

Students and professionals in physics, particularly those studying optics and gas behavior, as well as researchers focusing on the properties of gases under varying pressure conditions.

Aeon
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Dependence of refractive index on pressure

Homework Statement


Show that, in a gas (for which the refractive index is close to 1), the refractive index depends on the pressure as n_r = 1+ K\times p, and find the value of K.

Homework Equations



n_r = 1+ K\times p
Clausius-Mossotti equation: \frac{\epsilon_r - 1}{\epsilon_r + 2} = \frac{\rho N_a \alpha}{3M\epsilon_0}
\alpha^'\ = \frac{\alpha}{4\pi \epsilon_0}
n_r = \epsilon_r^{1/2}

The Attempt at a Solution



Any help to get me started, conceptual or mathematical, will be appreciated!

PS: I think I have posted this question in the right forum now. I had posted it in Advanced Physics before... I would have deleted my other post, but I can't.
 
Last edited:
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Which quantity on the right-hand side depends on the pressure p?

ehild
 
Supposing you're talking about the Clausius equation, I would say \frac{\rho}{M} = \frac{1}{V_m} depends on the pressure (inversely to how it behaves in phase diagrams).
 
The problem confuses me. I don't understand how I can go from the Clausius equation to <br /> n_r = 1+ K\times p<br />
 
Think of the ideal gas law. What is the relation between density and pressure?

ehild
 
i got confused
 
\rho = \frac{mp}{nRT}

To be honest, I'm starting to think I don't even NEED the Clausius equation to solve this problem...

Do I?
 
You do. Check the ideal gas law. It is wrong as you wrote it.
The symbol n in the ideal gas low means number of moles, n= mass/molar mass. And look after the meaning of the symbols in the Clausius equation.

ehild
 

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