What is the relationship between the acceleration and the angle of the slope?

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Homework Help Overview

The discussion revolves around calculating the kinetic friction of a block sliding down an inclined plane and determining its acceleration. The original poster questions whether this can be achieved without knowing the mass of the blocks, given the available equipment and measurements.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the relationship between acceleration, net force, and friction. There are attempts to apply Newton's second law and free body diagrams to understand the dynamics of the block on the slope. Questions arise about the necessity of mass in calculations and how acceleration can be utilized without it.

Discussion Status

Some participants have provided guidance on using Newton's second law and the concept of dividing equations by mass to simplify the problem. However, there remains confusion about the specific formulas and how to derive the coefficient of kinetic friction from the given data.

Contextual Notes

Participants note constraints such as the lack of digital scales for measuring mass and the reliance on given values like acceleration, angle, and gravity. There is an ongoing exploration of how these factors interact in the context of the problem.

Ocis
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Homework Statement


To calculate the kinetic friction of a block of wood and determine its acceleration by timing it as it travels down a slope. The equipment available consists: of a plank of wood, clamps etc. for raising one end of it to give an inclined plane, blocks to slide down the plane, weights which may be attached to the blocks, measuring equipment, and a timer.Can this be achieved without knowing the mass of the blocks? Because despite being allowed to use weights the equipment doesn't mention digital scales...
Known data: height & distance (slope), time, angle(Ө), acceleration. Us (static coe.)

Homework Equations


Us = TanӨ (Ө being angle of slope)
Uk = Ff= P+mgsinӨ (P =Applied Force)
Nf mgCosӨ

The Attempt at a Solution


I have already completed the results to get the Us (static coefficient) = TanӨ . I know that if the weight of the block is doubled so will the frictional force, but I am unsure how the acceleration helps to solve the Uk? Have I missed something? Thanks.
 
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For the case of a block accelerating down the slope, identify the forces acting and apply Newton's 2nd law. (Draw the usual free body diagram.) That might help you understand how measuring the acceleration allows you to calculate the coefficient of kinetic friction.
 
I know that the acceleration is directly proportional to the net force, and that the forces are therefore unbalanced to create an acceleration. I have drawn a f.b.d. but I am struggling to appreciate what good acceleration is without a mass or force to calculate the Uk...? Anymore clues or suggestions would be appreciated..
 
Welcome to PF!

Ocis said:
I have drawn a f.b.d. but I am struggling to appreciate what good acceleration is without a mass or force to calculate the Uk...?

Hi Ocis! Welcome to PF! :smile:

The acceleration perpendicular to the slope is zero, so the normal force is the same as before.

Then just use Newton's second law for forces parallel to the slope.

You don't need to know the mass, because mass will be in all the forces on the left-hand-side, and you should have mass x acceleration on the right-hand-side.

So just divide the whole equation by mass! :biggrin:
 
I would love to say I understand but I am even more confused now... What formula/equation are you referring to exactly. I can appreciate that the normal force is the same but its determining the applied force from just an acceleration? Am I expected to work this out from just having values of acceleration, angle, gravity? Sorry...
 
Ocis said:
What formula/equation are you referring to exactly.

Hi Ocis! :smile:

Total force along the slope = mass x acceleration along the slope.

In other words: mgsinθ - µN = m x acceleration.

So µ = … ? :smile:
 

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