1. The problem statement, all variables and given/known data What is the resutant torque about the hinge? known data: CCW force 280N, CW force 400, see diagram attached for all data. All red drawings are done by me. Black is the original problem. 2. Relevant equations M = F * perpendicular distance D. 3. The attempt at a solution Ok. This was my method. For the right side of the hinge I drew the equivalent angle of 40 deg to the 30 cm bar. 30cm cos40deg gave me the perpendicular distance of 22.96 cm I performed the same thing on the left side of the hinge. I cut the 90deg in half and drew a line to the line of sight of the hinge. I assumed it was half of 90. 60cos45deg gave me 42.426cm so now Mhinge = 400N*0.2296m - 280N*0.4243m = -26.964N So the resultant torque is a CCW force of 26.964 N. My buddy got an answer of -90.87 N. Thanks in advance.