Torque on a current loop about a hinge line

  • Thread starter theowne
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  • #1
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Homework Statement



A rectangular 20 turn loop that is 12 by 5 cm carries a current of 0.10A. It's hinged at one of the longer 12cm sides. It's mounted with its plane at an angle of 33 degrees to the direction of a magnetic field of 0.50T. What's the torque about the hinge line?

Homework Equations



T = iAbsin(theta)

The Attempt at a Solution



I guess my question is about the significance on the hinge line. The example in my book hinges on the z axis located in the middle of loop, so it uses the formula:

t = 2iaB (b/2) sin (theta)
where b/2 sin(theta) is decribed as the "moment arm". When it is hinged on the left longer side instead of the z axis, does this mean the equation would become 2iaB b sin (theta) instead?
 

Answers and Replies

  • #2
tiny-tim
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Hi theowne ! :smile:

(have a theta: θ :wink:)
The example in my book hinges on the z axis located in the middle of loop, so it uses the formula:

t = 2iaB (b/2) sin (theta)
where b/2 sin(theta) is decribed as the "moment arm". When it is hinged on the left longer side instead of the z axis, does this mean the equation would become 2iaB b sin (theta) instead?

There's various ways of looking a this (including actually working it out from scratch :wink:), but the easiest is probably to add a second loop next to the first, making one big loop with a hinge in the middle! :smile:
 

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