Torque on a current loop about a hinge line

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SUMMARY

The discussion centers on calculating the torque of a rectangular 20-turn loop, measuring 12 by 5 cm, carrying a current of 0.10A, hinged at one of its longer sides. The torque is determined using the formula T = iAbsin(theta), where the angle theta is 33 degrees and the magnetic field strength is 0.50T. The conversation highlights the significance of the hinge line's position, suggesting that the torque equation changes based on whether the loop is hinged at the center or at the left longer side. The proposed adjustment to the torque equation is t = 2iaB b sin(theta) when hinged at the left side.

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  • Understanding of torque calculations in physics
  • Familiarity with magnetic fields and their effects on current loops
  • Knowledge of the formula T = iAbsin(theta)
  • Basic concepts of moment arms in rotational dynamics
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  • Study the derivation of torque equations for different hinge points in current loops
  • Explore the effects of varying magnetic field strengths on torque
  • Learn about the implications of multiple loops in magnetic fields
  • Investigate the role of moment arms in calculating torque in various configurations
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Students in physics, particularly those studying electromagnetism, as well as educators seeking to clarify concepts related to torque and magnetic fields in current loops.

theowne
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Homework Statement



A rectangular 20 turn loop that is 12 by 5 cm carries a current of 0.10A. It's hinged at one of the longer 12cm sides. It's mounted with its plane at an angle of 33 degrees to the direction of a magnetic field of 0.50T. What's the torque about the hinge line?

Homework Equations



T = iAbsin(theta)

The Attempt at a Solution



I guess my question is about the significance on the hinge line. The example in my book hinges on the z axis located in the middle of loop, so it uses the formula:

t = 2iaB (b/2) sin (theta)
where b/2 sin(theta) is decribed as the "moment arm". When it is hinged on the left longer side instead of the z axis, does this mean the equation would become 2iaB b sin (theta) instead?
 
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Hi theowne ! :smile:

(have a theta: θ :wink:)
theowne said:
The example in my book hinges on the z axis located in the middle of loop, so it uses the formula:

t = 2iaB (b/2) sin (theta)
where b/2 sin(theta) is decribed as the "moment arm". When it is hinged on the left longer side instead of the z axis, does this mean the equation would become 2iaB b sin (theta) instead?

There's various ways of looking a this (including actually working it out from scratch :wink:), but the easiest is probably to add a second loop next to the first, making one big loop with a hinge in the middle! :smile:
 

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