What is the resulting force acting on water tank walls?

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SUMMARY

The discussion focuses on calculating the force exerted by water pressure on the walls of two types of tanks: a cylindrical tank and a cuboid tank. The calculations provided indicate that the force on the walls of the cylindrical tank is 30 kN and for the cuboid tank, it is 39.24 kN, based on a water pressure of 9810 Pa. However, a critical point raised is that the pressure on the sides of the tanks is not constant and varies with the height of the water, necessitating a reevaluation of the total resulting force acting at a third of the way up the wall.

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halfaguava
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Hello,

I am trying to calculate the force exerted by the water pressure on the walls of two different water tanks. A cylindrical tank and a cuboid tank.

Are the following calculations correct? (It seems too easy!)

Using generic dimensions:

Cylindrical Tank: Height 1m, Diameter 1m
Cuboid Tank: 1m × 1m ×1m
Tanks are full: P = \rhogh= 1000 × 9.81 × 1 = 9810Pa

Internal Surface Area of Cylindrical Tank: \pi × 1 × 1 = \pim^3
Internal Surface Area of Cuboid Tank: 1 × 1 × 4sides = 4m^3

F = P × A

Force on Walls of Cylindrical Tank: 30kN
Force of Walls of Cuboid Tank: 39.24kN

Thanks in advance!
 
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The problem with that is that the pressure on the sides isn't constant. The pressure on the sides is dependent on how much water is above that point.
 
In that case, I have calculated the total resulting force acting at a third of the way up the wall?
 

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