What is the rockets momentum after the course change?

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SUMMARY

The momentum of a rocket after a course change is determined by its mass and velocity, calculated using the formula momentum = mv. In this case, with a mass of 2000 kg and a forward velocity of 15000 m/s, the initial momentum is 30,000,000 kg·m/s. However, the change in direction due to the thrust from side rockets (25000 N) affects the momentum vectorially, necessitating consideration of the thrust's impact on mass and trajectory. The discussion emphasizes that momentum is a vector quantity, and any change in direction, even without a change in speed, alters the momentum.

PREREQUISITES
  • Understanding of momentum as a vector quantity
  • Familiarity with Newton's second law of motion
  • Basic knowledge of trigonometric functions, specifically tangent
  • Concept of thrust and its effect on mass in rocket propulsion
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  • Explore the principles of rocket propulsion and fuel consumption
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sidge2222
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Homework Statement



A rockets course needs to be diverted by one degree. The mass of the rocket is 2000kg, and its forward velocity is 15000ms. The rocket has side rockets with a thrust of 25000N with which to effect course change.

a) What is the rockets momentum after the course change?
b) How long must a side rocket fire to effect the required course change?

Homework Equations



momentum = mv
f = change in mv/t
tan angle = sum of i/sum of j

The Attempt at a Solution




if momentum = mv, then 2000 x 15000 = 30,000,000.
im pretty sure the answer is not as simple as this due to the change in the angle, but I am thinking the change in the angle won't effect the momentum of the rocket because the velocity and mass remain the same.

Am i missing something here guys or is it really that simple?

Thanks for reading, Sidge
 
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sidge2222 said:
if momentum = mv, then 2000 x 15000 = 30,000,000.
im pretty sure the answer is not as simple as this due to the change in the angle, but I am thinking the change in the angle won't effect the momentum of the rocket because the velocity and mass remain the same.

Am i missing something here guys or is it really that simple?

Thanks for reading, Sidge

Momentum is a vector quantity. A change in direction counts, even if the speed of the rocket doesn't change. So there's a \Deltap that was accomplished by expending fuel. That's going to reduce the mass of the rocket accordingly, and change the magnitude of the momentum.
 
Thanks for the response gneill.

Ok, so if i need calculate a change in angle by one degree, i would use the equation of tan angle = sum of i/sum of j, and then arrange these values until i alter the angle by one degree.

That sound right guys?

Thanks, Sidge
 
sidge2222 said:
Thanks for the response gneill.

Ok, so if i need calculate a change in angle by one degree, i would use the equation of tan angle = sum of i/sum of j, and then arrange these values until i alter the angle by one degree.

That sound right guys?

Thanks, Sidge

Consider that the problem statement doesn't explain *how* the 25000N thrust is created. In the real world, this would be by throwing out fuel mass at some high velocity (a rocket engine). This changes the mass of fuel on board the ship at it fires, etc., with all the subsequent details.

But here there are no details about the thrusters other than the force they can apply. So why not assume that they are "magic" and don't consume any ship's mass?

Now consider what happens when you apply a constant thrust at right angles to the instantaneous velocity. What shape trajectory happens?
 

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