What is the rockets momentum after the course change?

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Homework Help Overview

The discussion revolves around a rocket's momentum and course change due to thrust. The problem involves calculating the momentum after a one-degree course change, given the rocket's mass, velocity, and thrust from side rockets.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to calculate momentum using the formula momentum = mv, questioning the impact of the course change on momentum. Some participants discuss the vector nature of momentum and the implications of changing direction while maintaining speed. Others explore the relationship between thrust and mass change during the course correction.

Discussion Status

Participants are actively engaging with the problem, raising questions about the assumptions in the problem statement, particularly regarding the nature of the thrust and its effect on mass. There is a recognition that the change in direction affects momentum, but no consensus has been reached on the specifics of the calculations or assumptions.

Contextual Notes

The problem lacks details on how the thrust is generated and whether it affects the rocket's mass, leading to varied interpretations of the scenario. Participants are considering the implications of thrust direction and the resulting trajectory.

sidge2222
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Homework Statement



A rockets course needs to be diverted by one degree. The mass of the rocket is 2000kg, and its forward velocity is 15000ms. The rocket has side rockets with a thrust of 25000N with which to effect course change.

a) What is the rockets momentum after the course change?
b) How long must a side rocket fire to effect the required course change?

Homework Equations



momentum = mv
f = change in mv/t
tan angle = sum of i/sum of j

The Attempt at a Solution




if momentum = mv, then 2000 x 15000 = 30,000,000.
im pretty sure the answer is not as simple as this due to the change in the angle, but I am thinking the change in the angle won't effect the momentum of the rocket because the velocity and mass remain the same.

Am i missing something here guys or is it really that simple?

Thanks for reading, Sidge
 
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sidge2222 said:
if momentum = mv, then 2000 x 15000 = 30,000,000.
im pretty sure the answer is not as simple as this due to the change in the angle, but I am thinking the change in the angle won't effect the momentum of the rocket because the velocity and mass remain the same.

Am i missing something here guys or is it really that simple?

Thanks for reading, Sidge

Momentum is a vector quantity. A change in direction counts, even if the speed of the rocket doesn't change. So there's a \Deltap that was accomplished by expending fuel. That's going to reduce the mass of the rocket accordingly, and change the magnitude of the momentum.
 
Thanks for the response gneill.

Ok, so if i need calculate a change in angle by one degree, i would use the equation of tan angle = sum of i/sum of j, and then arrange these values until i alter the angle by one degree.

That sound right guys?

Thanks, Sidge
 
sidge2222 said:
Thanks for the response gneill.

Ok, so if i need calculate a change in angle by one degree, i would use the equation of tan angle = sum of i/sum of j, and then arrange these values until i alter the angle by one degree.

That sound right guys?

Thanks, Sidge

Consider that the problem statement doesn't explain *how* the 25000N thrust is created. In the real world, this would be by throwing out fuel mass at some high velocity (a rocket engine). This changes the mass of fuel on board the ship at it fires, etc., with all the subsequent details.

But here there are no details about the thrusters other than the force they can apply. So why not assume that they are "magic" and don't consume any ship's mass?

Now consider what happens when you apply a constant thrust at right angles to the instantaneous velocity. What shape trajectory happens?
 

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