What is the role of atmospheric refraction in a sunset?

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SUMMARY

The discussion focuses on the role of atmospheric refraction in the observation of sunsets, emphasizing the use of Snell's Law and ray diagrams for accurate representation. Participants highlight the importance of a clearly labeled ray diagram to illustrate how light bends as it passes through varying densities in the atmosphere. The equations discussed include Snell's Law (n1sin(θ1) = n2sin(θ2)) and the lens formula (1/f = 1/o + 1/i). A correct understanding of these concepts is essential for explaining the visual phenomena associated with sunsets.

PREREQUISITES
  • Understanding of Snell's Law and its application in optics
  • Familiarity with ray diagrams and their components
  • Knowledge of the lens formula and its variables
  • Basic concepts of atmospheric density and its effect on light refraction
NEXT STEPS
  • Study the application of Snell's Law in different mediums
  • Learn how to construct and interpret ray diagrams effectively
  • Research the impact of atmospheric conditions on light dispersion
  • Explore advanced optics concepts related to lenses and focal points
USEFUL FOR

Students studying physics, particularly those focusing on optics and atmospheric science, as well as educators looking to enhance their teaching methods regarding light behavior in varying mediums.

cris9288
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Homework Statement


Explain, with the relevant equations and a clearly labeled figure, what is actually happening as you view a sunset. Make sure to include a clearly labeled ray diagram for full credit.


Homework Equations



n1sin(θ1) = n2sinθ2

1/f = 1/o + 1/i

The Attempt at a Solution


This was a midterm problem that I got wrong. We are having an extra credit quiz tomorrow and this is the only problem I don't have solved.

My attempted solution involved using snells law, in both equation and diagram form. However I was given no credit as I had the "wrong approach". I'm guessing I should be using a ray diagram, but I'm unsure how to set up the f and i variables. Since the sun is very far away from the sun, I can set o in my lens equation to infinity. This would make the focal length equal to the image distance, but this really doesn't make any sense to me. Any help is appreciated, thanks.
 
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welcome to pf!

hi cris9288! welcome to pf! :smile:
cris9288 said:
Explain, with the relevant equations and a clearly labeled figure, what is actually happening as you view a sunset. Make sure to include a clearly labeled ray diagram for full credit.

My attempted solution involved using snells law, in both equation and diagram form.

i suspect your diagram was bad

can you show us (or describe) your diagram?

(and you don't seem to be mentioning colour)
 
Thing is, the atmosphere represents a medium with continuously varying index of refraction, both as a function of atmospheric density and dispersion (n varies with f).
 

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