What is the simplified form of 2 log (x2 - 1) - log (x + 1) - 2 log (x - 1)?

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SUMMARY

The simplified form of the expression 2 log (x² - 1) - log (x + 1) - 2 log (x - 1) is log (x + 1). By applying logarithmic laws, specifically x log n = log (n^x) and log m - log n = log (m/n), the expression can be transformed into log ((x² - 1)² / ((x + 1)(x - 1)²)). Recognizing that x² - 1 factors into (x - 1)(x + 1) allows for cancellation, leading directly to the simplified result.

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Hello again..

Homework Statement

I
I have to change this to one term only, the valid answer is: log (x + 1)

The term is: 2 log (x2 - 1) - log (x + 1) - 2 log (x - 1)

Homework Equations


Logarithmic laws:

x log n = log nx
log m - log n = log (m/n)

The Attempt at a Solution


I have tried dividing them but I don't see to be getting anywhere or anywhere close at all at the answer, I also tried factorising but I cannot figure it out, I'm pretty sure that it has some factorization (perfect squares? not sure what they're called in english..)

Thank you in advanced, this forum is a very useful resource!
 
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So you said you tried dividing. That gives log ( (x2-1)2/((x+1)(x-1)2) ). Now you just need to use the fact that (x2-1)=(x-1)(x+1), and some things will cancel out.
 
Note that x2-1=(x+1)(x-1)

Use some indices and you should get it.
 
The exact thing I needed!

Thank you guys, I can't appreciate this enough.
 

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