What is the solution for a PDE using method of characteristics?

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Homework Statement



solve using method of characteristics
[tex] <br /> y \frac{ \partial u}{ \partial x} - x \frac{ \partial u}{ \partial y}= 1<br /> [/tex] where u(x,0) = 0 for 0<x<infinity

The Attempt at a Solution



[tex] <br /> \frac{ \partial y}{ \partial x} = \frac{x}{y}<br /> [/tex] which gives [tex]y^2+x^2= k[/tex] the projected characteristic. but its the second part that is giving me trouble when i go to find [tex] <br /> \frac{ \partial u}{ \partial x} = \frac{1}{y}<br /> [/tex] which doesn't work out right...any suggestion anyone?
 
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tiny-tim said:
hi gtfitzpatrick! :smile:

(have a curly d: ∂ :wink:)

∂y/∂x = x/y gives y2 minus x2 = k :wink:


my mistake it should have read

∂y/∂x = -x/y gives y2 + x2 = k

but don't know how to work the second part?
 
oh and hi back :smile: