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## Homework Statement

The question is;

Two ropes hold a 200N weight as shown here; http://i.imgur.com/BgeoIVq.png

Find the tension in each rope using a vector diagram.

The forces are in equilibrium in the diagram btw.

## Homework Equations

Well they gave us 200N so no need for F = MA

Rx = R * cos(theta)

Ry = R * sin(theta)

The above are resolution to component equations.

Other equations the teacher gave us were:

tan(theta) = Ry/Rx

R = SQRT[(Rx)^2 + (Ry)^2]

The above are component to resolution equations.

## The Attempt at a Solution

So I fished around on this site and there were some solutions to this question, but I never quite got it, partially because (theta) for R2 is 90.

R1y = R1 * sin(53)

R2y = R2 * sin(90)

Downwards force = 200N

Therefore; because of equilibrium;

R1sin(53) + R2sin(90) = 200N [First Equation ( Y Axis )]

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R1x = R1 * cos(53)

R2x = R2 * cos(90)

Therefore; because of equilibrium;

R1cos(53) = R2(cos90) [Second Equation (X Axis)]

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Okay, the problem here is cos(90) = 0,

So does that mean that R1 = 0? because 0* R2 = 0.....

So the answer I got is

R1 = 0

R2 = 200

Im pretty sure that im wrong, but then again i only just started physics in year 11 (australia)