What is the solution for x^2 = 78 (mod 41503)?

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The congruence x^2 = 78 (mod 41503) can be solved by determining if 78 is a quadratic residue modulo 41503. The discussion emphasizes using quadratic reciprocity to verify this condition. If a solution exists, one can find a positive integer satisfying the congruence by substituting values for k in the equation x^2 - 78 = 41503k. A brute force method is suggested, testing small integer values for k to identify a valid solution.

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Determine whether or not the following congruence has a solution:
x^2 = 78 (mod 41503). If a solution exist then find a positive integer that satisfies the solution. Here, = means "congruent to".

I understand the fact that if 78 is the quadratic residue of 41503 then we have a solution but I don't know how I should do that? Should I break down 78 into factors of prime and then try to verify using quadratic reciprocity? Assuming that there IS a solution, how do I find an integer that satisfies the congruent? Please help! thanks!
 
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So x2 - 78 [itex]\equiv[/itex] 0 mod 41503, or
x2 - 78 = 41503k, for some integer k.

A brute force approach would be to substitute five of ten values for k (such as 1 through 5 or 10), and see if you can get a solution. The problem asks for only one solution, and you might get lucky and find one this way.
 

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