What is the solution of this differential equation?

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The discussion focuses on solving the differential equation (ax+y)∂f/∂x + (ay+x)∂f/∂y = 0, with the specific condition that when a=0, f(x,y) equals x^2 - y^2. Participants explore methods such as using the total differential and the relationship between partial derivatives to analyze the equation. A suggested approach involves a change of variables that simplifies the problem significantly. The conversation emphasizes the importance of understanding the implications of the variable 'a' on the solution. Ultimately, the thread seeks to clarify the steps needed to solve the given partial differential equation effectively.
Esmaeil
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how can we solve this differential equation?
(ax+y)∂f/∂x + (ay+x)∂f/∂y =0 with this condition: if a=0 then f(x,y)=x^2 - y^2
 
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Esmaeil said:
how can we solve this differential equation?
(ax+y)∂f/∂x + (ay+x)∂f/∂y =0 with this condition: if a=0 then f(x,y)=x^2 - y^2
df=\frac{∂f}{∂x}dx+\frac{∂f}{∂y}dy

At constant f, \frac{∂f}{∂x}dx+\frac{∂f}{∂y}dy=0

Or equivalently, \left(\frac{∂y}{∂x}\right)_f=-\frac{(∂f/∂x)}{(∂f/∂y)}

Chet
 
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The change of variables (in attachement) leads to a very simple PDE :
 

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