What is the Solution to a Function and Roots Problem?

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Homework Help Overview

The discussion revolves around a function problem involving the square root function, specifically F(X) = √x, and the evaluation of an expression that includes F((F(2)-2)^2) + F(2). Participants are exploring the implications of negative values within the square root and the overall evaluation of the expression.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants are attempting to simplify the expression and are questioning the impact of negative signs in their calculations. There is also a suggestion to clarify the notation used in the function.

Discussion Status

The discussion is ongoing, with participants providing hints and engaging in a back-and-forth about the evaluation of the expression. Some participants express uncertainty about the signs and their effects on the outcome.

Contextual Notes

There is mention of a potential misunderstanding regarding the notation used in the function, and participants are navigating through the implications of negative values in their calculations.

Patrickas
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Homework Statement


F(X)=√x
F((F(2)-2)^2)+f(2)

Homework Equations





The Attempt at a Solution

I get to √(-4√2 +8) ... that minus sign is annoying me =] any help?
 
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Hi Patrickas! :smile:

(try using the X2 tag just above the Reply box :wink:)
Patrickas said:
F(X)=√x
F((F(2)-2)^2)+f(2)

I get to √(-4√2 +8) ... that minus sign is annoying me =] any help?

(do you mean F((F(2)-2)2) + F(2) ?)

Hint: F(a2) = … ? :smile:
 
tiny-tim said:
Hi Patrickas! :smile:

(try using the X2 tag just above the Reply box :wink:)


(do you mean F((F(2)-2)2) + F(2) ?)

Hint: F(a2) = … ? :smile:


Hmmm I'm guessing that the signs will change. Then i should get -√2+2+√2= 2
Right?
 
Patrickas said:
Hmmm I'm guessing that the signs will change. Then i should get -√2+2+√2= 2
Right?

Yup! :biggrin:
 
tiny-tim said:
Yup! :biggrin:

Cool! Thanks! I wonder hoe long will i remember this rule =]
 

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