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sona1177
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Homework Statement
A cylindrical disk has volume 8.97 x 10^-3 m^3 and mass 8.16 kg. The disk is floating on the surface on some water with its flat surfaces horizontal. The area of each flat surface is .640 m^2. What is the specific gravity of the disk? How far below the water level is its bottom surface? How far above the water level is its top surface?
I know that the S.G. is .9097, and the density is 909.70 kg/m^3. So Vsubmerged = (Density of disk x Volume of disk)/density of fluid.
I got a value of .00816 m^3.
Then from Vsubmerged=Area x depth under water =.00816/.640=.01275 m
The last question is the one I am unsure about.
I subtracted the value of the object from V submerged to get 8.1 x 10^-4 for the volume not submerged (above water) and got 8.1 x 10^-4. So then V =Ad and V/A= 8.1 10^-4/.640=.01266 m.
I am not sure that I did the last part correctly, can you please tell me if I took the right approach?