What Is the Speed of an Arrow at the Top of Its Flight?

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SUMMARY

The discussion centers on calculating the speed of an arrow at the apex of its flight, launched at a 45-degree angle and covering a horizontal distance of 950 meters. The initial velocity (Vi) was calculated to be 96.54 m/s, but there is uncertainty regarding its accuracy. Participants are encouraged to verify the initial velocity and apply projectile motion principles to determine the speed at the top of the flight.

PREREQUISITES
  • Understanding of projectile motion principles
  • Basic trigonometry for angle calculations
  • Knowledge of kinematic equations
  • Familiarity with the concept of initial velocity in physics
NEXT STEPS
  • Review the kinematic equations for projectile motion
  • Learn how to calculate the vertical and horizontal components of velocity
  • Study the effects of launch angle on projectile trajectories
  • Explore the concept of maximum height in projectile motion
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This discussion is beneficial for physics students, educators, and anyone interested in understanding the dynamics of projectile motion and the calculations involved in determining velocities at various points in a projectile's flight.

mochilili
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any help is much appreciated!

Sarah sent a arrow a horizontal distance of 9.5X10^2 m. What was the speed of the arrow at the top of the flight if the arrow as launched at an angle of 45 degrees with respect to the horizontal?


i figured out the Vi, which was 96.54. But, I'm not sure what to do from there.
 
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Hi mochilili,

mochilili said:
any help is much appreciated!

Sarah sent a arrow a horizontal distance of 9.5X10^2 m. What was the speed of the arrow at the top of the flight if the arrow as launched at an angle of 45 degrees with respect to the horizontal?


i figured out the Vi, which was 96.54. But, I'm not sure what to do from there.

What did you do to find that initialvelocity? I don't think it is quite right.
 

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