What Is the Speed of Water at the Top of Della Falls?

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SUMMARY

The speed of water at the top of Della Falls, which has an elevation change of 440 meters, can be calculated using energy conservation principles. When the water has fallen 12% of the distance, its speed is 33 m/s. The calculated speed at the top of the waterfall is 7.35 m/s, while the textbook incorrectly states it as 5.0 m/s due to using an approximate value of 10 m/s² for gravitational acceleration instead of the more accurate 9.8 m/s².

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Homework Statement



The highest waterfall in Canada is the Della Falls in British Columbia, with a change
in elevation of 4.4  102 m. When the water has fallen 12% of its way to the bottom,
its speed is 33 m/s. Neglecting air resistance and fluid friction, determine the speed
of the water at the top of the waterfall.


Homework Equations



E before = E after
1/2 mv^2 + mgh = 1/2 mv^2 + mgh
v^2 + 2gh = v^2 + 2gh
v^2 = v^2 + 2gh - 2gh
v = √v^2 + 2gh - 2gh



The Attempt at a Solution




GIVENS:

waterfall distance from ground = 440m
V2= 33m/s
water fallen at 12% distance = 387.2m


v = √v^2 + 2gh - 2gh
v = √(33m/s)^2 + 2(9.8 m/s^2)(387.2m) - 2(9.8 m/s^2)(440m)
v=7.35m/s


now the answer in the book is 5.0m/s and i was wondering what is the mistake that is made ?? or is the book just incorrect?


thank you for your help in advance..
 
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Start with kinetic + potential at 440 m is equal to kinetic plus potential at 387.2 meters. Use different symbols for the speed v and the height h. Your problem is you plugged the numbers in the wrong places because everything looks the same.
 
thanks will work on it n message back
 
tamir102 said:
thanks will work on it n message back

your answer 7.35 m/s is correct
the only reason it says 5.0 m/s in the book is because the book uses
10m/s for gravity because it is for easier calculations
thanks for helping me with a waterfall physics question
 
i actually went to my physics teacher and he said the same thing you said cad.
 

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