What is the Speed v2 of the Mouse and the 0.25-kg Cart?

  • Thread starter Thread starter Angela_vaal
  • Start date Start date
  • Tags Tags
    Elastic
Click For Summary
SUMMARY

The discussion centers on a physics problem involving a 0.038-kg mouse and a 0.35-kg air-track cart, which after the mouse jumps to a second cart of 0.25 kg, results in the first cart moving at a speed of v1=0.86 m/s. The participants clarify that the collision is inelastic, as the mouse sticks to the second cart after jumping. The relevant conservation law applicable here is the conservation of momentum, which governs the system's behavior due to the absence of external forces on the frictionless track.

PREREQUISITES
  • Understanding of conservation of momentum
  • Knowledge of elastic and inelastic collisions
  • Familiarity with basic physics equations related to kinetic energy
  • Concept of frictionless surfaces in physics
NEXT STEPS
  • Study the principles of conservation of momentum in collision scenarios
  • Explore the differences between elastic and inelastic collisions
  • Review examples of momentum conservation in multi-object systems
  • Learn about the implications of frictionless surfaces in physics problems
USEFUL FOR

Students studying physics, educators teaching mechanics, and anyone interested in understanding collision dynamics and conservation laws in a frictionless environment.

Angela_vaal
Messages
59
Reaction score
1

Homework Statement


A 0.038-kg pet lab mouse sits on a 0.35-kg air-track cart, as shown in (Figure 1) . The cart is at rest, as is a second cart with a mass of 0.25 kg. The lab mouse now jumps to the second cart. After the jump, the 0.35-kg cart has a speed of v1=0.86m/s.

What is the speed v2 of the mouse and the 0.25-kg cart?
fig_9-27.png


Homework Equations


1/2m1v02=1/2m1v1,f2+1/2m2v2,f2

The Attempt at a Solution


I don't know where to start. I am assuming this is an elastic collision since the carts don't stick together after the collision. Would I use the equation listed above? I just don't know how to start
 
Last edited:
Physics news on Phys.org
I don't know if 'not sticking together' ensures an elastic collision ...

And if the speeds beforehand were zero, then afterwards they must be zero too ?
Do you think there is conservation of kinetic energy in this case ?
What about the work mickey mouse does when kicking away the 0.35 kg block ?

Know any other conservation laws ? (in fact, one other is already enough...:smile: )
 
The mouse "sticks" to the second cart, so at least part of the scenario involves a collision that is not an elastic one.

What conservation law does your relevant equation express? Is there another quantity that's conserved that might be a better choice for the overall scenario?Edit: Ah! BvU got there before me!
 
gneill said:
The mouse "sticks" to the second cart, so at least part of the scenario involves a collision that is not an elastic one.

What conservation law does your relevant equation express? Is there another quantity that's conserved that might be a better choice for the overall scenario?Edit: Ah! BvU got there before me!

Is the collision inelastic then?
 
I'm confused.
 
Angela_vaal said:
Is the collision inelastic then?
It's not a single collision scenario. The mouse pushes off the first cart with what might be interpreted as an inelastic collision in reverse (separation instead of joining) and then collides with and sticks to the second cart in another inelastic collision.

The good news is that one conservation law covers the whole process from start to finish.
 
And what is this conservation law?
 
Angela_vaal said:
Is the collision inelastic then?
You should never assume collisions are elastic without good reason. If you can solve without that assumption, do so.
As others have told you, there is another conservation law available. You must have been taught it. It applies to a system (two carts plus mouse in this case) provided there are no external forces acting on the system in the direction of interest. Since the track is frictionless, there are no external horizontal forces on that system, so the law applies in that direction.
 

Similar threads

  • · Replies 13 ·
Replies
13
Views
6K
  • · Replies 8 ·
Replies
8
Views
5K
  • · Replies 24 ·
Replies
24
Views
4K
  • · Replies 6 ·
Replies
6
Views
7K
  • · Replies 1 ·
Replies
1
Views
4K
  • · Replies 16 ·
Replies
16
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 9 ·
Replies
9
Views
3K
Replies
4
Views
2K
  • · Replies 16 ·
Replies
16
Views
4K