What is the spring constant of spring?

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Homework Help Overview

The problem involves a scenario where a person drops onto a platform supported by a spring, and the goal is to determine the spring constant. The context includes concepts of gravitational potential energy and spring mechanics.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to apply energy conservation principles but questions their calculations regarding the effective distance the mass falls. Some participants clarify the total distance the person falls, including the compression of the spring.

Discussion Status

The discussion is ongoing, with participants exploring the implications of the total drop distance and confirming the need to include the spring compression in calculations. There is no explicit consensus yet, but clarification on the problem setup is being provided.

Contextual Notes

Participants are addressing the assumption that the total drop distance should include both the initial drop and the spring compression. The original poster's calculations are based on an incomplete understanding of the total distance fallen.

Mdhiggenz
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Homework Statement


A 60 kg person drops from rest a distance of 1.20 m to a platform of negligible mass supported by a stiff spring. The platform drops 6 cm before the person comes to rest. What is the spring constant of spring?


Homework Equations





The Attempt at a Solution



w=1/2kx^2

mgh=1/2kx^2

2(mgh)/x^2=k

2(60kg*9.8*1.20)/0.06m=3.92*10^5

the answer however is 4.12*10^5


What am I doing wrong?

Thank you
 
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The mass falls further than 1.20 as the spring compresses.
 
So would I add the 0.06m? Iam a bit confused
 
Correct. :smile:

The question says …
Mdhiggenz said:
A 60 kg person drops from rest a distance of 1.20 m to a platform

… after that it drops a further 0.06 m, so the total drop (for the person) is 1.26 m :wink:
 
Thx Tim
 

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