What is the spring constant of spring?

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Mdhiggenz
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Homework Statement


A 60 kg person drops from rest a distance of 1.20 m to a platform of negligible mass supported by a stiff spring. The platform drops 6 cm before the person comes to rest. What is the spring constant of spring?


Homework Equations





The Attempt at a Solution



w=1/2kx^2

mgh=1/2kx^2

2(mgh)/x^2=k

2(60kg*9.8*1.20)/0.06m=3.92*10^5

the answer however is 4.12*10^5


What am I doing wrong?

Thank you
 
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The mass falls further than 1.20 as the spring compresses.
 
So would I add the 0.06m? Iam a bit confused
 
Correct. :smile:

The question says …
Mdhiggenz said:
A 60 kg person drops from rest a distance of 1.20 m to a platform

… after that it drops a further 0.06 m, so the total drop (for the person) is 1.26 m :wink: