What is the stopping distance of the car?

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SUMMARY

The stopping distance of a car traveling at 12.0 m/s, after a reaction time of 0.510 seconds and subsequent deceleration of 6.20 m/s², is calculated to be 17.72 meters. Initially, the car travels 6.12 meters during the reaction time. After the brakes are applied, the stopping distance is determined using the equation vf² = vi² + 2ad, resulting in an additional 11.6 meters. Therefore, the total stopping distance is the sum of both distances.

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Suppose a car traveling at 12.0m/s sees a traffic light turn red. After 0.510s have elapsed, the driver applies the brakes, and the car decelerates at 6.20m/s^2. What is the stopping distance of the car, as measured from the point where the driver first notices the red light?


Homework Equations



d=vt
vf^2=vi^2+2ad



The Attempt at a Solution



d before breaking
d=vt
=12(0.51)
d=6.12m

d after breaking

vf^2=vi^2+2ad
0^2=12^2+2(-6.20)d
-144=2(-6.20)d
d=11.6m
 
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