What is the tallest straw that you could, in principle, drink from

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The maximum height of a straw from which one can drink water is determined to be 10 meters, based on the approximation of gravitational acceleration at 10 m/s². The fundamental principle involves atmospheric pressure pushing the water up the straw, which can be calculated using the equation P1 + ρgh1 = P2 + ρgh2. In this scenario, P1 is 0 Pa and h1 is 0, leading to the conclusion that P2 equals atmospheric pressure, which supports a height of 10 meters for water.

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As a stunt, you want to sip some water through a very long, vertical straw. what is the tallest straw that you could, in principle, drink from in this way?
 
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Well, what do you think?
 
well i know the answer is 10 m if you round gravity to 10 m/s^2. i also know that the pressure on the top of the straw is 0 Pa. but besides that i have no clue, that's why I am asking it.
 
When you sip through a straw, what pushes the water up the straw?
 
the vacuum created by sucking your cheeks in.
i came up with this solution.
P1 + rough (g) (h1) = P2 + rough (g) (h2)
P1=0, h1=0
so P2 = rough (g)(h2)
1 atm= 1000(10)(h2)
1.01 EE5=1.0EE4(h2)
h2= 10 m

but I am not sure.
 
Looks like you've got it. It's atmospheric pressure that pushes the water up the straw. The maximum height of water that can be supported by the air will be found by setting the water pressure (\rho g h) equal to atmospheric pressure.
 

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