What is the Time-Evolved State of a Single-Mode Cavity Field?

Click For Summary

Homework Help Overview

The discussion revolves around the time-evolved state of a single-mode cavity field in quantum mechanics. The original poster presents a state at time t=0 and seeks to find its evolution over time.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the application of the Schrödinger equation for time evolution and question the energy levels associated with the states involved. There is exploration of how to express the time-evolved state based on initial conditions and energy eigenvalues.

Discussion Status

The conversation is actively exploring the correct application of quantum mechanics principles, particularly regarding energy states and their evolution. Some participants have provided guidance on substituting energy values into the time-evolved state equation, while questions about the common phase factor remain open.

Contextual Notes

Participants are navigating the implications of different energy levels for the states |n⟩ and |n+1⟩, and there is an ongoing inquiry into the definitions and values of these energy levels.

Confundo
Messages
36
Reaction score
0

Homework Statement



Suppose the state of a single-mode cavity field is given at time t=0 by

[tex] |\Psi(0) \rangle = \frac{1}{\sqrt{2}}(|n \rangle + e^{i\phi}|n+1 \rangle)[/tex]

where phi is some phase. Find the state [tex]|\psi(t)\rangle[/tex] at times t > 0.

Homework Equations



I'm a little confused of what to do with this one, I know that [tex]|n\rangle = \frac{(\hat a^{\dagger})^n}{\sqrt{n!}}|0\rangle[/tex] and think I make have to substitue for the n eigenvalue using that somehow of that somehow and integrate.
 
Last edited:
Physics news on Phys.org
What equation determines the time evolution of any state in quantum mechanics?

Apply that equation!
 
The SE.

Just
[tex] |\Psi(t) \rangle = e^\frac{-iEt}{\hbar}|\Psi(0) \rangle = e^\frac{-iEt}{\hbar}\frac{1}{\sqrt{2}}(|n \rangle + e^{i\phi}|n+1 \rangle)[/tex] ?
 
No...do the states |n> and |n+1> have the same energy?
 
[tex] |\Psi(t) \rangle = \frac{1}{\sqrt{2}}(e^\frac{-iE_{n}t}{\hbar}|n \rangle + e^\frac{-iE_{n+1}t}{\hbar}e^{i\phi}|n+1 \rangle)[/tex]
 
yeah...and what are the values of E_n and E_{n+1}?
 
[tex]E_n = \hbar \omega(n + 0.5)[/tex]
[tex]E_{n+1} = \hbar \omega(n + 1.5)[/tex]
 
Right, substitute that in your last equation, take a common phase factor out, done.
 
How does the common phase factor come out?
 
  • #10
That follows from [tex]\exp(i\phi) \exp(i\phi')=\exp(i(\phi+\phi'))[/tex]
 

Similar threads

Replies
1
Views
2K
  • · Replies 0 ·
Replies
0
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 6 ·
Replies
6
Views
4K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 0 ·
Replies
0
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 1 ·
Replies
1
Views
3K