What is the Torque on a Looped Wire in a Uniform Magnetic Field?

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SUMMARY

The torque on an eight-turn coil in a uniform magnetic field can be calculated using the formula Torque = N * A * I * B * sin(θ). In this case, the coil encloses an elliptical area with a major axis of 40.0 cm and a minor axis of 30.0 cm, resulting in a semimajor axis (a) of 20.0 cm and a semiminor axis (b) of 15.0 cm. The correct area (A) is calculated as A = πab, yielding approximately 0.376 m². With a current (I) of 5.85 A and a magnetic field (B) of 2.02 x 10-4 T, the torque is determined to be 0.00356 N·m when the angle (θ) is 90 degrees.

PREREQUISITES
  • Understanding of torque calculation in physics
  • Familiarity with the properties of ellipses
  • Knowledge of magnetic fields and their effects on current-carrying coils
  • Proficiency in using the formula Torque = N * A * I * B * sin(θ)
NEXT STEPS
  • Study the derivation and application of the torque formula in electromagnetic contexts
  • Learn about the properties and equations related to ellipses, specifically area calculations
  • Explore the effects of varying angles on torque in magnetic fields
  • Investigate the behavior of coils in different magnetic field orientations
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Physics students, electrical engineers, and anyone involved in electromagnetic theory or applications will benefit from this discussion.

ketchuppy
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Problem:

An eight turn coil encloses an elliptical area having a major axis of 40.0 cm and a minor axis of 30.0 cm. The coil lies in the plane of the screen and has a 5.85 A current flowing clockwise around it. If the coil is in a uniform magnetic field of 2.02 10-4 T directed toward the left of the screen, what is the magnitude of the torque on the coil? (Hint: The area of an ellipse is A = πab, where a and b are, respectively, the semimajor and semiminor axes of the ellipse.)

19-p-027.gif


I'm not sure what I'm doing wrong because this is plug in and calculate problem with the equation for torque. I'm guessing the angle would be 90 in this case so sin 90 = 1. The answer i came up with was .00356 N*M
 
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Hi ketchuppy,

ketchuppy said:
Problem:

An eight turn coil encloses an elliptical area having a major axis of 40.0 cm and a minor axis of 30.0 cm. The coil lies in the plane of the screen and has a 5.85 A current flowing clockwise around it. If the coil is in a uniform magnetic field of 2.02 10-4 T directed toward the left of the screen, what is the magnitude of the torque on the coil? (Hint: The area of an ellipse is A = πab, where a and b are, respectively, the semimajor and semiminor axes of the ellipse.)

19-p-027.gif


I'm not sure what I'm doing wrong because this is plug in and calculate problem with the equation for torque. I'm guessing the angle would be 90 in this case so sin 90 = 1. The answer i came up with was .00356 N*M


Please post the details of what you did (as in, what numbers you used and what you did with them). My guess is that you read the hint incorrectly and used 40cm and 30cm for a and b, but without your work I can't be certain.
 
I used the equation Torque = NAIB Sin angle

N= 8
A= .376 m^2
I = 5.85
B= 2.02 10-4 T
for the angle i used 90 degrees
 
ketchuppy said:
I used the equation Torque = NAIB Sin angle

N= 8
A= .376 m^2

I believe this area is incorrect, which is what I was referring to in my last post. The problems gives numerical values for the major axis and minor axis (40 cm and 30cm).

But in the hint, the values of a and b to use in the area formula are the semimajor and semiminor axis.
 
alphysicist said:
I believe this area is incorrect, which is what I was referring to in my last post. The problems gives numerical values for the major axis and minor axis (40 cm and 30cm).

But in the hint, the values of a and b to use in the area formula are the semimajor and semiminor axis.

TY I didn't see that it was semi. =)
 

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