What is the total energy of the body at x=4 meters?

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Homework Help Overview

The discussion revolves around calculating the total energy of a body moving along the x-axis under the influence of a force defined by Fx = -6x N. The body has a mass of 2.9 kg and an initial velocity at a specific position.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants are attempting to determine the velocity of the body at x = 4 m and the total energy at different positions. There are questions regarding the correct equations to use for calculating kinetic and potential energy.

Discussion Status

Multiple participants are sharing their calculations and questioning the equations being used. Some have expressed uncertainty about the correctness of their results and the formulas applied, indicating an ongoing exploration of the problem.

Contextual Notes

Participants are discussing the potential confusion surrounding the use of initial velocity and the correct expression for total energy, which includes both kinetic and potential energy components.

sciencegeek26
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The only force acting on a 2.9 kg body as it moves along the positive x-axis has an x component Fx = - 6x N, where x is in meters. The velocity of the body at x = 3.0 m is 8.0 m/s.

What is the velocity of the body at x=4?

At what positive value of x will the body have a velocity of 5 m/s?

I got the answer to the second question just fine, which ended up being 5.3. I feel like I just am doing the first one wrong. What is the proper equation for it? I thought it would be
-6/2(4^2-3^2). Or at least that is what my teacher said would give me the correct answer. Alas that is not so. I just need the proper way to do the first one now.
 
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What's the total energy of the body at x = 3 and at x = 4? Set up an equation and then you can solve for the speed.
 
I got it to be -21J but I think I'm using the wrong equation
 
sciencegeek26 said:
I got it to be -21J but I think I'm using the wrong equation
What equation are you using?
 
Doc Al said:
What equation are you using?

(1/2)m(v2^2-3^2)

Instead of 3 being squared should it be 8m/s? Then I would get -69.6J
 
sciencegeek26 said:
(1/2)m(v2^2-3^2)

Instead of 3 being squared should it be 8m/s? Then I would get -69.6J
You need to fix that formula. The total energy is the sum of the kinetic energy and the spring potential energy. How would you express spring potential energy?
 

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