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What is the total force exerted by block 2 on block 3 ?

  1. Jan 29, 2013 #1
    Four blocks EACH of mass m = 10.0 kg are arranged as shown in the picture, on top of a frictionless table. A hand touching block 1 applies a force of Fh1 = 90.0 N to the right. The coefficient of friction between the blocks is sufficient to keep the blocks from moving with respect to each other.

    What is the total force exerted by block 2 on block 3 ?

    I got 67.5 N which was wrong

    F=90N-22.5=67.5N since a=9/4ms-2
     

    Attached Files:

  2. jcsd
  3. Jan 29, 2013 #2

    tms

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    Start by drawing a free-body diagram showing all the forces. Pay particular attention to blocks 2 and 3, but don't ignore the others.
     
  4. Jan 29, 2013 #3
    I now think block 2 would exert a force to block 3 equal to the combined weight of the 2 books above it which is f=2(mg) = 2*10*9.8 = 196 N

    but i still get it wrong
     
  5. Jan 29, 2013 #4

    tms

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    That's part of it, but what about the horizontal direction?
     
  6. Jan 29, 2013 #5
    i got it now its sqrt(of horizontal direction ^2 + vertical direction ^2)
     
  7. Jan 29, 2013 #6

    tms

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    Assuming you are referring to the forces on the block, that is indeed the magnitude of the net force. Now what is the direction?
     
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