What is the total translational kinetic energy of the gas molecules

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SUMMARY

The total translational kinetic energy (Ktr) of 0.450 mol of air at atmospheric pressure occupying a volume of 5.00 L can be calculated using the formula P = (2/3)(N/V). Given that atmospheric pressure is 101.3 kPa, the necessary values can be substituted into the equation to derive Ktr. Additionally, the translational kinetic energy of a single gas molecule is expressed as KE = (3/2)kT, where k is the Boltzmann constant and T is the temperature in Kelvin.

PREREQUISITES
  • Understanding of the Ideal Gas Law (PV = nRT)
  • Familiarity with the concept of translational kinetic energy
  • Knowledge of the Boltzmann constant (k)
  • Basic skills in unit conversions (e.g., atm to kPa)
NEXT STEPS
  • Learn how to apply the Ideal Gas Law to calculate pressure and temperature
  • Study the derivation of translational kinetic energy from kinetic theory
  • Explore the relationship between pressure, volume, and temperature in gases
  • Investigate the implications of gas behavior under different conditions (e.g., varying temperature and pressure)
USEFUL FOR

Students in physics or chemistry courses, educators teaching gas laws, and anyone interested in the kinetic theory of gases and thermodynamics.

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Homework Statement


What is the total translational kinetic energy of the gas molecules of 0.450 mol of air at atmospheric pressure that occupies a volume of 5.00 L (0.00500 m3)?


Homework Equations


P=2/3(N/V)<Ktr>
N= 0.450 mol
V= 5.00L
Want to find Ktr


The Attempt at a Solution


The problem is I don't know the pressure to use this formula or how to figure out what it is from the given information, if that's possible.
 
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Well, atmospheric pressure is 1 atm = 760 mm Hg = 101.3 kPa.

If you need more help, given that the translational kinetic energy of one molecule of gas is KE = 3kT/2, use the formula PV = NkT to derive the formula for the case that you're dealing with.
 

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