Finding the Kinetic Energy of a particle in 2mol of nitrogen

[DracoMalfoy]

Homework Statement

What is the kinetic energy of a particle in 2mol of nitrogen gas at atmospheric pressure that is within a volume of 100m^3?


a. 1.27X10^-17J
b. 3X10^5J
c. 6.8X10^-16J
d. 2.97X10^7
e. 9.9X10^-14J

Homework Equations

PV=nRT
n=Numberof particles/Na
Na=6.02x10^23
R=8.13 J/Mol

The Attempt at a Solution

[/B]
I know that atmospheric pressure is 1.013x10^5. The nitrogen part is what confuses me. I'm not sure where to start in solving this.

 

[phyzguy]

What does the kinetic energy of a particle in a gas depend on? Does it depend on the pressure? The volume? If not, then what?

 

[DracoMalfoy]

What does the kinetic energy of a particle in a gas depend on? Does it depend on the pressure? The volume? If not, then what?

I honestly don't know. I'm too frustrated to think straight at the moment. I am mad that I am not getting this.

 

[phyzguy]

I honestly don't know. I'm too frustrated to think straight at the moment. I am mad that I am not getting this.

Do you have a book or course notes you can review? Have you talked about ideal gas theory in class?

 

[DracoMalfoy]

Do you have a book or course notes you can review? Have you talked about ideal gas theory in class?

yes. we just learned this yesterday. i guess id have to look through the book. The teacher isn't very good. the class notes given are a bit confusing to understand

 

[gneill]

You may also find that Hyperphysics web site to be a great resource that succinctly summarizes specific topics.

Hint: Do a web search on Kinetic Temperature

 

[DracoMalfoy]

You may also find that Hyperphysics web site to be a great resource that succinctly summarizes specific topics.

Hint: Do a web search on Kinetic Temperature

Thanks. Ill check it out. I tried again and got A. But the powers came out different on my calculator.

 

[phyzguy]

Thanks. Ill check it out. I tried again and got A. But the powers came out different on my calculator.

Can you show us how you arrived at answer A?