What Is the True Energy Cost of Achieving a Fusion Energy Gain Factor?

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SUMMARY

The discussion centers on the fusion energy gain factor (Q) in fusion reactors, specifically the JET, ITER, and DEMO projects. The JET recorded a Q factor of 0.7 in 1997, while ITER is expected to achieve a Q of 10 and DEMO a Q of 25. The conversation highlights the necessity of including all energy inputs, particularly the power required for toroidal magnets, to accurately assess the Q factor. For a fusion power station to achieve breakeven, the Q factor must exceed 20, factoring in energy consumption for current drive, refueling, profile control, and burn control.

PREREQUISITES
  • Understanding of fusion energy principles
  • Familiarity with the concept of energy gain factor (Q)
  • Knowledge of magnetic confinement systems in fusion reactors
  • Basic grasp of superconducting electromagnets and their efficiency
NEXT STEPS
  • Research the energy requirements for toroidal magnets in fusion reactors
  • Explore the ITER interactive simulator for practical insights on fusion energy dynamics
  • Investigate the differences between scientific and engineering Q-values
  • Learn about the BTI bubble detector and its application in amateur fusion experiments
USEFUL FOR

This discussion is beneficial for fusion energy researchers, engineers involved in reactor design, and enthusiasts in the field of nuclear fusion seeking to understand the complexities of energy gain factors and reactor efficiency.

stevebd1
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I have a general interest in fusion energy and I'm currently looking at the 'fusion energy gain factor' (Q) of fusion reactors (the energy produced divided by the energy used to induce ignition). I'm aware that the JET recorded a Q factor of 0.7 in 1997, the ITER is anticipated to have a Q factor of 10 and the DEMO a Q factor of 25. The Q factor doesn't include the energy used to power the toroidal magnets and I would be interested to know what power these would require and by how much superconducting electromagnets would reduce energy use (power consumption being negligible in the steady field state for SC electromagnets). I've read that for a fusion power station to break even, the Q factor would have to be over 20 due to the power required for current drive, refuelling, profile control and burn control, I'd be interested to know how the factor of 20 'breaks down' regarding these different aspects of energy use (specifically the powering ot the toroidal magnets).

regards
Steve
 
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stevebd1 said:
I have a general interest in fusion energy and I'm currently looking at the 'fusion energy gain factor' (Q) of fusion reactors (the energy produced divided by the energy used to induce ignition). I'm aware that the JET recorded a Q factor of 0.7 in 1997, the ITER is anticipated to have a Q factor of 10 and the DEMO a Q factor of 25. The Q factor doesn't include the energy used to power the toroidal magnets and I would be interested to know what power these would require and by how much superconducting electromagnets would reduce energy use (power consumption being negligible in the steady field state for SC electromagnets). I've read that for a fusion power station to break even, the Q factor would have to be over 20 due to the power required for current drive, refuelling, profile control and burn control, I'd be interested to know how the factor of 20 'breaks down' regarding these different aspects of energy use (specifically the powering ot the toroidal magnets).

regards
Steve
One has to properly define Q for it to be useful. I've learned scientific Q vs engineering Q-values.

Here is a reasonable discussion. Technically the energy input must includes all energy inputs including that used to establish and maintain confinement.

Wikipedia said:
The fusion energy gain factor, usually expressed with the symbol Q, is the ratio of fusion power produced in a nuclear fusion reactor to the power required to maintain the plasma in steady state.
http://en.wikipedia.org/wiki/Fusion_energy_gain_factor

It doesn't address all the details and nuances, but it is one I can readily get my hands on. :rolleyes:
 
Thanks for the reply Astronuc. I sent an email to EURATOM/UKAEA Fusion Association at Culhum Science Centre asking the same question but I'm yet to get a reply.

One thing I did find on the web was an interactive simulator for ITER (you can choose between ITER 85 and 05) where you decide the strength of the magnetic confinement, the power input and amount of fuel used (a dial tells you underneath how much power you are using). You can also configure the cross section of the plasma to obtain optimum output. Dials to the left tell you how much energy you're producing (taking into account the energy used). Apparently, you should get an output of 1000 MW. Though obviously this isn't hard evidence of the energy used by the magnetic confinement, it's still an interesting simulation.

Link- http://fusion.gat.com/diii-d_global/simulation/jstar/
 
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stevebd1 said:
Thanks for the reply Astronuc. I sent an email to EURATOM/UKAEA Fusion Association at Culhum Science Centre asking the same question but I'm yet to get a reply.

One thing I did find on the web was an interactive simulator for ITER (you can choose between ITER 85 and 05) where you decide the strength of the magnetic confinement, the power input and amount of fuel used (a dial tells you underneath how much power you are using). You can also configure the cross section of the plasma to obtain optimum output. Dials to the left tell you how much energy you're producing (taking into account the energy used). Apparently, you should get an output of 1000 MW. Though obviously this isn't hard evidence of the energy used by the magnetic confinement, it's still an interesting simulation.

Link- http://fusion.gat.com/diii-d_global/simulation/jstar/

Hey, that's fun! I had found something similar a while back, it looks about the same here.

I got 1405 MW of electrical output. I suppose the introductory fusion class helped. :smile:
 
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stevebd1 said:
I have a general interest in fusion energy and I'm currently looking at the 'fusion energy gain factor' (Q) of fusion reactors (the energy produced divided by the energy used to induce ignition).

Steve,

Q simply refers to the energy quotient as you describe above, and by rights all energy should be taken into consideration. There are always suspicions that the big labs fiddle the numbers and leave out some important information to make the numbers look better. After all they depend on getting more funding next year.

I atttach a pdf file that gives some information about Q from the JET reactor in Culham.

As you may be aware, I belong to a group of amateur fusioneers at www.fusor.net and we have a simple method of calculating Q, where we include all energy in (except the energy required to drive vacuum pumps).

I have set up a permanent Q calculator at

http://www.beejewel.com.au/research/fusion_calculator.htm"

,that anyone with a bubble detector can use, even the big guys if they dare :)

The reason we trust the BTI bubble detector is that all electronic detectors are subject to interference by EMF and we have found that neutron readings are often overstated.

In world of amateur fusion we are still aiming to break the Q 1e-8 barrier http://www.fusor.net/board/view.php?bn=fusor_construction&key=1212188288"

Have fun..

Steven
 

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