What is the uncertainty in this result?

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SUMMARY

The uncertainty in the density calculation of a rectangular block, given a mass of (25.0 ± 0.1)g and dimensions of (5.00 ± 0.01)cm, (2.00 ± 0.01)cm, and (1.00 ± 0.01)cm, is determined to be 2.50 ± 0.053 g/cm³. The initial calculation incorrectly applied the percentage uncertainties for mass and volume, leading to a density percentage uncertainty of 0.5%. However, the correct approach requires summing the percentage uncertainties, resulting in a total density percentage uncertainty of 2.1%. This adjustment leads to the final density representation of 2.50 ± 0.053 g/cm³.

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Homework Statement


The density of the material of a rectangular block is determined by measuring the mass and linear dimensions of the block. The table shows the results obtained, together with their uncertainties.

Mass = (25.0 \pm 0.1)g
Lenght = (5.00 \pm 0.01)cm
Breath = (2.00 \pm 0.01)cm
Height = (1.00 \pm 0.01)cm

The density is calculated to be 2.50gcm^-3
What is the uncertainty in this result?

Homework Equations


Density = Mass / Volume
Percentage Uncertainty = Acutal Uncertainty / True Value * 100

The Attempt at a Solution



Mass % Uncertainty = \frac{0.1}{25.0} \times 100 = 0.4\%
Lenght % Uncertainty = \frac{0.01}{5.00} \times 100 = 0.2\%

Breath % Uncertainty = \frac{0.01}{2.00} \times 100 = 0.5\%

Height % Uncertainty = \frac{0.01}{1.00} \times 100 = 1\%

Density % Uncertainty = \frac{Mass \% Uncertainty}{Volume \% Uncertainty} = \frac{0.4}{0.2+0.5+1} = 0.5\%

Absoulte Value = \frac{0.5 \times 2.50}{100} = 0.0125gcm^-3

Density = 2.50 \pm 0.0125 gcm^-3

Is this right?

 
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looi76 said:
Mass % Uncertainty = \frac{0.1}{25.0} \times 100 = 0.4\%
Lenght % Uncertainty = \frac{0.01}{5.00} \times 100 = 0.2\%

Breath % Uncertainty = \frac{0.01}{2.00} \times 100 = 0.5\%

Height % Uncertainty = \frac{0.01}{1.00} \times 100 = 1\%


You are fine up to here.

Density % Uncertainty = \frac{Mass \% Uncertainty}{Volume \% Uncertainty} = \frac{0.4}{0.2+0.5+1} = 0.5\%


Sadly, perhaps, percentages of uncertainty don't divide in this way. In products and quotients, the percentages of uncertainty always add. (This can be shown from differentiation of products or quotients to solve for what are called "relative errors".)

The percentage of uncertainty in the density will be

0.4% (for the mass) + [0.2% + 0.5% + 1.0%] (for the volume product) = 2.1% .

So the density would be reported as

2.50 gm/(cm^3) +/- 2.1% or 2.50 +/- 0.053 gm/(cm^3) .

You can check this by looking at the density value obtained by using the highest mass in the uncertainty range divided by the smallest volume in its uncertainty range, and then the lowest mass divided by the largest volume. The agreement won't be exact because the "rules of thumb" for handling percentages of uncertainty are only approximate (the agreement is ideal only for infinitesimal changes).
 

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