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Homework Statement
The density of the material of a rectangular block is determined by measuring the mass and linear dimensions of the block. The table shows the results obtained, together with their uncertainties.
Mass [tex]= (25.0 \pm 0.1)g[/tex]
Lenght [tex]= (5.00 \pm 0.01)cm[/tex]
Breath [tex]= (2.00 \pm 0.01)cm[/tex]
Height [tex]= (1.00 \pm 0.01)cm[/tex]
The density is calculated to be [tex]2.50gcm^-3[/tex]
What is the uncertainty in this result?
Homework Equations
Density = Mass / Volume
Percentage Uncertainty = Acutal Uncertainty / True Value * 100
The Attempt at a Solution
Mass % Uncertainty [tex]= \frac{0.1}{25.0} \times 100 = 0.4\%[/tex]
Lenght % Uncertainty [tex]= \frac{0.01}{5.00} \times 100 = 0.2\%[/tex]
Breath % Uncertainty [tex]= \frac{0.01}{2.00} \times 100 = 0.5\%[/tex]
Height % Uncertainty [tex]= \frac{0.01}{1.00} \times 100 = 1\%[/tex]
Density % Uncertainty = [tex]\frac{Mass \% Uncertainty}{Volume \% Uncertainty} = \frac{0.4}{0.2+0.5+1} = 0.5\%[/tex]
Absoulte Value = [tex]\frac{0.5 \times 2.50}{100} = 0.0125gcm^-3[/tex]
Density = [tex]2.50 \pm 0.0125 gcm^-3[/tex]
Is this right?
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