What is the unit vector parallel to A at point P(1,-1,2)?

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Bingo1915
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How can I calculate the following?
Given A=[tex]\hat{x}[/tex](x+2y)-[tex]\hat{y}[/tex](y+3z)+[tex]\hat{z}[/tex](3x-y)
Determine a unit vector parallel to A at point P(1,-1,2).
 
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It's straight forward substitution. Find the vector A at the given point and then calculate the unit vector by scaling A by the inverse of its length (thus making the new vector's length one).
 
I agree. By substitution A=-1i-5j+4z, The magnitude of A = Sqrt((-1)2+(-5)2+(4)2). Divide the magnitude into A to get the unit vector.