What is the Value of the Pocket Knife?

  • Thread starter Thread starter d-rock
  • Start date Start date
  • Tags Tags
    Cs Puzzle
Click For Summary

Discussion Overview

The discussion revolves around a mathematical problem involving two farmers, their cows, sheep, and a goat, culminating in determining the value of a pocket knife used as compensation during the division of livestock. The scope includes mathematical reasoning and problem-solving related to a test scenario.

Discussion Character

  • Homework-related
  • Mathematical reasoning
  • Debate/contested

Main Points Raised

  • One participant states their answer to the problem is $2 and seeks unbiased opinions on the solution.
  • Another participant claims to have a different answer and is asked to explain their reasoning.
  • A participant provides a detailed breakdown of their reasoning, concluding that if there are 6 cows, the value of the knife must be $2 to equalize the value of livestock between the two farmers.
  • One participant initially calculated a different value ($4) but later revised their answer to $2 after careful consideration.
  • There is mention of professors disagreeing with the initial answer, adding to the complexity of the discussion.

Areas of Agreement / Disagreement

Participants express differing views on the correct value of the pocket knife, with some supporting the $2 conclusion while others have proposed alternative values. The discussion remains unresolved as multiple competing views are present.

Contextual Notes

Participants note that the problem involves various assumptions about the number of cows and the resulting calculations for sheep and goat purchases, which may affect the final answer. The problem's constraints and the interpretation of the livestock values are also under scrutiny.

Who May Find This Useful

This discussion may be useful for individuals interested in mathematical problem-solving, particularly in scenarios involving optimization and compensation in resource allocation.

d-rock
Messages
14
Reaction score
0

Homework Statement


Two farmers have no more than 15 cows. They get as many dollars for each cow as they have cows. For example, if they have 3 cows then they get 3 dollars per cow so a total of 9 dollars.

After taking this money they bought as many sheep as possible at $10 a sheep. The remaining money was used to buy a goat. They did not have any money left over.

After the livestock was purchased the farmers decided to split up the livestock. Since there was an odd number of sheep, the one who took the goat got his friend's pocket knife as compensation since the goat was worth less than a sheep. How much is the pocket knife worth?

Homework Equations


None

The Attempt at a Solution


NOTE: As said below, this was a test problem that we've already finished. My answer was $2. There is a debate over the problem but I wanted unbiased opinions to compare.

I gave my solution in a few posts below, but I would like the problem worked out by people so I can see what others say on their own without being influenced by my post. Thanks.
 
Last edited:
Physics news on Phys.org
d-rock: I currently got a different answer than what you got.
 
What was your answer...?

If it is 4 then you will have to explain why, please. If not, then still explain why because then I won't have any clue how you got that.
 
d-rock said:

Homework Statement


Two farmers have no more than 15 cows. They get as many dollars for each cow as they have cows. For example, if they have 3 cows then they get 3 dollars per cow so a total of 9 dollars.

After taking this money they bought as many sheep as possible at $10 a sheep. The remaining money was used to buy a goat. They did not have any money left over.

After the livestock was purchased the farmers decided to split up the livestock. Since there was an odd number of sheep, the one who took the goat got his friend's pocket knife as compensation since the goat was worth less than a sheep. How much is the pocket knife worth?


Homework Equations


None


The Attempt at a Solution


This is actually more of seeing what answer you all get, because I wanted to come to a place where people could think through it.

Two of my professors told me that my answer is incorrect but I am 99% sure it is correct and I want to see what everyone else here gets. I got $2 as the answer.

Could you please show us how you got the $2 answer?
 
I got a different answer than 2.
 
d-rock: On this forum, the powers that be do not allow us to tell you how to solve your homework. They only allow us to check math. Did your professors give you the final answer? Or did they only tell you your current answer is incorrect?
 
It's not a homework problem. It was a test problem that we had and it's been a debate over the answer.

I will give my work below, but I would like an unbiased opinion and explanation for your answers please, so please work it before reading my below solution if you will. My professor has a different answer but a few others and I think he is wrong, so it's been a debate.


My solution
First, we must figure out the number of cows. There can be 1 through 15 cows. As a sheep costs $10, then the number of cows squared must be greater than 10.

Therefore, n_cows must be > 3 as 3^2 = 9. Furthermore, there is an odd number of sheep as stated in the problem, therefore 5, 7, 8, 9, 10, 11, 12, 13, and 15 do not work, as their squares will leave an even number (plus a remainder) when divided by 10.

So the set of number of cows possible is {4, 6, 14}. Let us just choose the number 6 for example.

6^2 = 36, so they have $36. The most possible sheep that can be bought is 3, leaving $6. As the rest of the money is used to buy the goat, then the goat's price is $6.

Now, they go to split up the livestock: 3 sheeps and 1 goat. Farmer A takes 2 sheep. Farmer B takes the last sheep and the goat. Farmer A has 2*10 = $20. Farmer B has 1*10 + 1*6 = $16.

Farmer A wishes to give a knife that he owns to Farmer B in order to make their values equal.

So, the value of the knife must be $2. If Farmer A loses the knife, he loses $2. This means $20 - $2 = $18. And Farmer B gains the knife, so he gains $2. $16 + $2 = $18.

Farmer A and Farmer B are both at $18. Therefore they are now equal.
 
d-rock: The first time I worked this problem quickly, I got $4, which is incorrect. After working it more carefully, I got the correct answer, $2. Nice work. Your answer, $2, is correct. Although, a small part of your explanation is slightly incorrect, and should instead be as follows. Let us choose the case having six cows.

Farmer A started out with $2 + 18 = $20, and ended up with $20. Farmer B started out with $18, and ended up with $16 + 2 = $18.

Nonetheless, you got the right answer. Excellent work.
 
nvn said:
d-rock: The first time I worked this problem quickly, I got $4, which is incorrect. After working it more carefully, I got the correct answer, $2. Nice work. Your answer, $2, is correct. Although, a small part of your explanation is slightly incorrect, and should instead be as follows. Let us choose the case having six cows.

Farmer A started out with $2 + 18 = $20, and ended up with $20. Farmer B started out with $18, and ended up with $16 + 2 = $18.

Nonetheless, you got the right answer. Excellent work.

I worked it as an optimization problem, and I read it wrong. I didn't put it that no more than 15. Too much of that voodoo economics.
 

Similar threads

  • · Replies 13 ·
Replies
13
Views
3K
  • · Replies 28 ·
Replies
28
Views
3K
Replies
5
Views
2K
  • · Replies 2 ·
Replies
2
Views
5K
  • · Replies 9 ·
Replies
9
Views
4K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 46 ·
2
Replies
46
Views
5K
Replies
3
Views
10K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 2 ·
Replies
2
Views
3K