What is the velocity of a body thrown into a pit?

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Homework Help Overview

The problem involves a body thrown vertically upward from a height of 1.5 m above the ground into a pit that is 3.5 m deep. The initial velocity of the body is given as 2.3 m/s, and the objective is to determine the velocity at which the body reaches the bottom of the pit.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the initial height and total height, with some questioning the setup of the problem and the equations used. There are attempts to clarify the height considerations and the application of kinematic equations.

Discussion Status

The discussion includes various interpretations of the problem setup, with some participants offering hints and guidance regarding the initial height. There is acknowledgment of potential confusion among participants, and some express confidence in their initial reasoning.

Contextual Notes

Participants note the importance of considering both the initial height and the total height in their calculations. There is a mention of previous discussions and advice from another participant, indicating a collaborative effort to understand the problem better.

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Homework Statement


A body is thrown vertically upward from the distance h = 1,5 m above the ground at the
edge of a pit having a depth of s = 3,5 m. The initial velocity of the body is 2,3 m/s.

Homework Equations


Determine the velocity at which the body will reach the bottom of the pit.

The Attempt at a Solution


(h=5m)

V2-V02=2gh
V=10.168 m/s
 
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What a violent problem...

I'll give you a hint, the initial height is 1.5m, but the total height is 3.5m.
 
flyingpig said:
What a violent problem...

I'll give you a hint, the initial height is 1.5m, but the total height is 3.5m.

really ?
 
chawki said:

The Attempt at a Solution


(h=5m)

V2-V02=2gh
V=10.168 m/s
Looks good.
 
Hello Doc Al, Thank you for your help on the last time regarding equations..i try not to mess up my mind with them.

regarding this actual problem, I'm starting to think that flying pig is right :/
 
chawki said:
regarding this actual problem, I'm starting to think that flying pig is right :/
Why is that?
 
Take Doc Al's advice. I just glanced over the problem and your equation. I just saw that you missed the initial height in your equation, so I jumped into a conclusion lol
 
flyingpig said:
Take Doc Al's advice. I just glanced over the problem and your equation. I just saw that you missed the initial height in your equation, so I jumped into a conclusion lol

ahaa..lol don't confuse me :smile: I'm easy to confuse :shy:
i'm glad i was right at the first try :smile:
 
This is how I'm imagining it...
 

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  • #10
Am i right ?
 
  • #11
chawki said:
Am i right ?
Yes.
 
  • #12
Doc Al said:
Yes.

Thank you :smile:
 
  • #13
i think you're right boy .. here's my solution

v^2 = Vo^2 - 2gy
Vo=2.3m/s
y=1.5+3.5 = 5m

V=2.3^2 -2(9.8)(-5)
V=10.16m/s downward ..

:approve:
 

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