What is the Velocity of Gliders A and B in an Inelastic Collision?

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SUMMARY

The discussion focuses on calculating the velocities of two gliders, A and B, during an inelastic collision. Glider A, with a mass of 0.269 kg and an initial velocity of 1.07 m/s, collides with glider B, which has a mass of 0.330 kg and an initial velocity of -0.675 m/s. The conservation of momentum equation is applied: m1v1 + m2v2 = (m1 + m2)v3, where v3 represents the common velocity after the collision. The total momentum before the collision is calculated and set equal to the joint momentum after the collision to solve for the final velocity.

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Given:

Two gliders on an air track collide. Glider A has a mass of 0.269 kg and is moving in the +x direction with a speed of 1.07 m/s. Glider B has a mass of 0.330 kg and is moving in the -x direction with a speed of 0.675 m/s. a) What is the velocity of A and B if the collision is completely inelastic? Calculate the velocities of b) A and c) B if the collision is completely elastic.

Im stuck on solving for the veloctiy of A + B if it in inelastic. I understand how to do it if it is elastic, just not sure what to do when KE is transfered.
 
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If the collision is completely inelastic then you don't need to worry about the energy.

setup the conservation of momentum equation like this:
m1v1 + m2v2 = (m1 + m2) v3
(m1 + m2) because they are stuck together post collision.

you have m1, m2, v1 and v2 so just solve for v3.
 
COMPLETELY inelastic means that the two objects stick together and move as one after the collision so you only have one variable, the common speed after the collision.
Before the collision, A's momentum was 0.269(1.07) kg and B's momentum was (0.33)(-0.675) so the total momentum was (0.269)(1.07)-(0.33)(0.675). Their joint momentum after the collision is (0.260+0.33)v. Set those equal and solve for v.
 
Thank you so much. I really do understand it now.
 

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