What is the Visual Prime Pattern Based on Trig and Harmonics?

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The discussion revolves around the concept of a visual prime pattern derived from trigonometry, square roots, and harmonic sequences, with links to visual representations provided. The creator expresses challenges in conveying their ideas due to being self-taught and seeks feedback on their approach, which involves using collision detection to analyze intersections of concentric circles and vertical lines. Participants explore the implications of replacing parabolas with straight lines and the relationship between prime numbers and their graphical representations. The conversation also touches on the significance of harmonic analysis and Fourier series in understanding these mathematical patterns. Overall, the thread highlights the intersection of advanced mathematics and visual representation, inviting further exploration and collaboration.
  • #91
And, Jeremy, Marin Mersenne, for whom Mersenne Primes are named, in relation to the pendulum...

via Wikipedia
-------------------------------------------------------------
http://en.wikipedia.org/wiki/Marin_Mersenne
Mersenne's description in the 1636 Harmonie universelle of the first absolute determination of the frequency of an audible tone (at 84 Hz) implies that he had already demonstrated that the absolute-frequency ratio of two vibrating strings, radiating a musical tone and its octave, is 1 : 2. The perceived harmony (consonance) of two such notes would be explained if the ratio of the air oscillation frequencies is also 1 : 2, which in turn is consistent with the source-air-motion-frequency-equivalence hypothesis.

He also performed extensive experiments to determine the acceleration of falling objects by comparing them with the swing of pendulums, reported in his Cogitata Physico-Mathematica in 1644. He was the first to measure the length of the seconds pendulum, that is a pendulum whose swing takes one second, and the first to observe that a pendulum's swings are not isochronous as Galileo thought, but that large swings take longer than small swings.[2]

-------------------------------------------------------------

To set a pendulum half period equal to exactly 1 second, then L/g = 1/pi^2.
To set a pendulum full period to exactly 1 second, then L/g = 1/4pi^2

pi^2 --> Idealized Acceleration due to Gravity * s^2/m (Denote g')
4pi^2 --> GM * s^2/m^3

...for GM the Gravitational Parameter and 4pi^2/GM the unit multiplier of Kepler's 3rd Law.

And bear in mind the following:

In an idealized mathematical environment, there is no mass, and, therefore, no friction to slow things down, although partial sums of infinite series do, in fact, often seem to simulate such.

84 Hz, by the way, maps to 1 Hz per note of the Circle of Fifths, which has 84 notes and 7 octaves. 84 is a Tetrahedral number, and at least up to 1.41*10^1504 (computer checked by CRGreathouse), the last one such that 1.5 times a Tetrahedral Number = 2^y - 2.

1.5 * 84 = 126 ==2^7 - 2 == Vertices of E_7 == totient(p_31)

31 (as is 7...) is a Doubly Mersenne Number (both a Mersenne Prime and Mersenne Prime Exponent) == Dimensions of E_8/8 == 496/16 for 496 the 3d Perfect Number.
Totient (496) = 240, the number of vertices of E_8, made famous by A. Garrett Lisi in his paper "An Exceptionally Simple Theory of Everything."

RELATED THREAD
A Tetrahedral Counterpart to Ramanujan-Nagell Triangular Numbers?
https://www.physicsforums.com/showthread.php?t=443958

A "fun" little related equivalency that may have nothing to do with physics, but at least a thing or two to do with building models:

299800649
= (G_(totient(56) + totient(70)) - (56 + 70))/10^2
= (G_48 - 126)/10^2
= (G_24-0*L_24+0 - 128)/10^2
= (G_24-6*L_24+6 + 128)/10^2
= 299792458 + 8191; [8191 = 2^13 - 1 is a Mersenne Prime = sqrt ((8190^2 + 2*8190) + 1) = sqrt (67092480 + 1)]

for G_n the Golden Scale
for L_n the Lucas Series

48 is the number of roots of F_4, while 56 & 70 are the (partitioned) roots of E_7. 24, of course, is the number of roots of D_4 [and p^2 - 1 == 0(mod 24) for all p>3] and 6 the number of roots of A_2.

- RF
 
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  • #92
I don't think I've mentioned this Jeremy, but the Golden Scale is important for the following reason:

It represents the optimal number of divisions of the octave (Mersenne studied the octave and the octonions are an increasingly significant mathematical player in Theoretical Physics). Thus, 5 (Black Keys - Pentatonic Scale) + 7 (White Keys - Diatonic Scale) = 12, the number of notes in the Chromatic scale. But you can also divide the octave quite nicely into 19, 31, 50, 81, 131, 212, 343, 555 increments and so on (note the palindromic structure...). 555 nanometers, by the way, "coincidentally" happens to be the wavelength for which human eyes are best "callibrated." Which would only be meaningful in any manner whatsoever other than "coincidence" should it ever come to be shown that our units of measure (such as the meter, kilogram and second) were not chosen "arbitrarily," but rather in consonance with "rhythms" that "spiraled up" (in fractal manner) from the deep sub-strata of our biological engineering in tandem with (dialectically) iterated scientific interaction with and application of those "rhythms" to the natural world of which we are a part.

As recently as early last year, that would have been a heretical notion (a point I can vouchsafe for given all the names I have been called and the censorship I have encountered for suggesting as much...). But in the past few years, that shamefully defamed proportion known as the Golden Ratio has been spotted in organic and quantum systems alike.

e.g.
Golden Ratio Discovered in Quantum World: Hidden Symmetry Observed for the First Time in Solid State Matter
excerpt
ScienceDaily (Jan. 7, 2010) — Researchers from the Helmholtz-Zentrum Berlin für Materialien und Energie (HZB), in cooperation with colleagues from Oxford and Bristol Universities, as well as the Rutherford Appleton Laboratory, UK, have for the first time observed a nanoscale symmetry hidden in solid state matter. They have measured the signatures of a symmetry showing the same attributes as the golden ratio famous from art and architecture.
http://www.sciencedaily.com/releases/2010/01/100107143909.htm

And the link I posted previously...
Period Concatenation Underlies Interactions between Gamma and Beta Rhythms in Neocortex
Frontiers in Neuroscience
Roopun, Kramer et al.
Received January 21, 2008; Accepted March 27, 2008.
http://www.ncbi.nlm.nih.gov/pmc/articles/PMC2525927/

RELATED THREAD
OBSERVATION: The #31, The Golden Scale, Prime Counting Function & Partition Numbers
https://www.physicsforums.com/showthread.php?t=469982

RELATED LINK
On Rabbits, Mathematics and Musical Scales
by John S. Allen
http://www.bikexprt.com/tunings/fibonaci.htm

Allen quotes the following by Sir James Jeans, Science and Music, pp. 163-164

"...vast numbers of tribes and cultures...developed music independently, and in the most varied surroundings...They exhibit enormous differences in their language, customs, clothes, modes of life and so forth, but all who have advanced beyond homophonic music have, if not precisely the same musical scale, at least scales which are built on the same principle..."

He also addresses the 7 +/- 2 rule in relation to music...

The seven-tone scales in the twelve-tone system approach the limit of what the human mind can assimilate. The rule of "seven plus or minus two" in sensory psychology states that for any sensory continuum, humans describe between five and nine different categories: to give an example, we describe the gray scale using the categories white, off-white, light gray, medium gray, dark gray, near black and black. Though we can discriminate more shades of gray when they are placed side by side for comparison, we do not give names to them, or use the discrimination between them as part of a conceptual structure based on unaided observation and memory.

So, now, bearing in mind the rule of 7, compare the following sets of numbers...

2* DIVISION OF 4-SPACE BY n-1 "CUTS" OF A HYPERPLANE + 2n
-----------------------------------------------------------------------
2*01 + 00 = 002
2*02 + 02 = 006
2*04 + 04 = 012
2*08 + 06 = 022
2*16 + 08 = 040
2*31 + 10 = 072
2*57 + 12 = 126

TOTIENT K_n + 1
-------------------------------------------------------
(totient 002 + 1) = 002
(totient 006 + 1) = 006
(totient 012 + 1) = 012
(totient 024 + 1) = 020
(totient 040 + 1) = 040
(totient 072 + 1) = 072
(totient 126 + 1) = 126

K_n
-------------------------------------------------------
K_1 = 002
K_2 = 006
K_3 = 012
K_4 = 024
K_5 = 040
K_6 = 072
K_7 = 126

(K_n + TOTIENT (K_n + 1))/2

= 0, 2, 6, 12, 22, 40, 72 126

--> 2* DIVISION OF 4-SPACE BY n-1 "CUTS" OF A HYPERPLANE + 2n for n = 1 --> 7

- RF

RELATED PROGRESSION
Maximal number of regions obtained by joining n points around a circle by straight lines. Also number of regions in 4-space formed by n-1 hyperplane
1, 2, 4, 8, 16, 31, 57, 99, 163, 256, 386, 562, 794, 1093, 1471, 1941, 2517, 3214, 4048, 5036, 6196, 7547, 9109, 10903, 12951, 15276, 17902, 20854, 24158, 27841, 31931, 36457, 41449, 46938, 52956, 59536, 66712, 74519, 82993, 92171, 102091
http://oeis.org/A000127

That the totient of 36457 (--> p_11 = 31 "cuts" of a 4-space), corresponding with a 32-gon = 36456 and B*10^11 = 36456 meters = totient (p_(12*Lucas_12)) meters [10 = totient (11), 12 = sigma(11)] is most surely a "coincidence" that I would not read into just because 32 (= sigma (p_11)) is the maximal number of electrons/shell and B = 3.6456*10^-7 meters is the Balmer Constant (without which we would not have the Bohr Model of the atom or the Rydberg Constant). Remember, this is SUDOKU and model building, not physics, and any "sane" person well knows that the division and partitoning of mathematical space has nothing whatsoever to do with the partitioning of cognitive and/or physical space [Notwithstanding the fact that the Crystallographic Restriction Theorem, the entire Science of Emission Spectroscopy, Miller (1956), and, more or less, the entire Standard Model of Physics (based on symmetries of 1, 3 & 8 dimensional lattices) are based on such ideas...]...

And the prime number distribution also, clearly, has nothing to do with any of the above. Never mind that a Random Matrix Physicist used quantum mechanics to correctly predict 24024 as the 4th unique "moment" of The Riemann Zeta Function. That was, quite clearly, just a lucky guess (Marcus du Sautoy talks about this prediction in "Music of the Primes")
 
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  • #93
Here, Jeremy, is an iterative scheme for deriving the Ramanujan-Nagell Pronics Union 1, which also follows the form x^2 + x for x = 1/phi

B = 0, 1, 2, 6, 30, 8190
0X --> (1/phi)

B = x^2 + x = p_(z_n) - 1
z_n = (2^(z_(n-1) - sgn(z_(n-1))) + (n-1))

0000 = 00^2 + 00 = (p'_0000 - 1); 0000
0001 = 0X^2 + 0X = (p'_0001 - 1); 0001 = (2^(00 - sgn(00)) + 0)
0002 = 01^2 + 01 = (p'_0002 - 1); 0002 = (2^(01 - sgn(01)) + 1)
0006 = 02^2 + 02 = (p'_0004 - 1); 0004 = (2^(02 - sgn(02)) + 2)
0030 = 05^2 + 05 = (p'_0011 - 1); 0011 = (2^(04 - sgn(04)) + 3)
8190 = 90^2 + 90 = (p'_1028 - 1); 1028 = (2^(11 - sgn(11)) + 4)

For G = Divisor of 12 (mod 12)= 0, 1 , 2, 3, 4, 6

Then Denote A as...
2^(G-2) + 2(G-2) = 0, 0, 1, 4, 8, 24

K_A = AB
K_A = 2^(G-2) + 2(G-2)*p_(z_n) - 1


Since the divisors of 12 = {0, 1, 2, 3, 5, 11} + 1, are all iterated "qrime" numbers {0, 1 UNION primes), now you only need two terms to generate the entire Unimodular scheme from 0 to 24.

In other words, beginning at 0, just press "start" and the whole "building" (K_0, K_0, K_1, K_4, K_8, K_24) basically builds itself.

The next term in the B series...
p_(~ 1.438154*10^309 + 6) - 1
... which gets a bit unwieldy without some kind of "reset" mechanism.

More here if you're interested...

https://www.physicsforums.com/showpost.php?p=3315364&postcount=486

- RF

RELATED PAPER
Kissing Numbers, Sphere Packings, and Some Unexpected Proofs
by Florian Pfender, Gunter M. Ziegler
http://mathdl.maa.org/mathDL/22/?pa=content&sa=viewDocument&nodeId=3065
 
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  • #94
Raphie,
I'm still digesting...Real quick thought. Is there a formula for the probability of a pendulum being at a given angle during its period? A conical pendulum to be exact.
 
  • #95
Raphie said:
I don't think I've mentioned this Jeremy, but the Golden Scale is important for the following reason:

It represents the optimal number of divisions of the octave (Mersenne studied the octave and the octonions are an increasingly significant mathematical player in Theoretical Physics). Thus, 5 (Black Keys - Pentatonic Scale) + 7 (White Keys - Diatonic Scale) = 12, the number of notes in the Chromatic scale. But you can also divide the octave quite nicely into 19, 31, 50, 81, 131, 212, 343, 555 increments and so on (note the palindromic structure...). 555 nanometers, by the way, "coincidentally" happens to be the wavelength for which human eyes are best "callibrated." Which would only be meaningful in any manner whatsoever other than "coincidence" should it ever come to be shown that our units of measure (such as the meter, kilogram and second) were not chosen "arbitrarily," but rather in consonance with "rhythms" that "spiraled up" (in fractal manner) from the deep sub-strata of our biological engineering in tandem with (dialectically) iterated scientific interaction with and application of those "rhythms" to the natural world of which we are a part.

Raphie,
I'm seeing the octonions connection in my recursion algorythm. This stuff is amazing... The link should be up now. I reworked it with a pop up menu. If it works for you try this combo; Click OK. Press "1", Press "Space bar", Press "v" twice, Notice the pendulum like motion, Press "2". Very interesting results. I'm not sure how to describe them. I hope this new version works for you.
Thanks again for all of this information, I'm seeing so many connections now and learning more than I ever have.

Jeremy

the link again:
http://www.tubeglow.com/test/PL3D2/P_Lattice_3D_2.html
You might have to upgrade your flash player. I'm using 10.1.102.64. 10.3.181.14 is MAC's latest.
 
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  • #97
Here is another link to the app if that one doesn't work.
http://dl.dropbox.com/u/13155084/PL3D2/P_Lattice_3D_2.swf
or
http://dl.dropbox.com/u/13155084/PL3D2/P_Lattice_3D_2.html
 
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  • #100
JeremyEbert said:
Sorry for the delay. I’ve been working on the next piece to this and got distracted by an interesting vector of this equation.

Sorry to jump around here but I think this is where I need some more help explaining the big picture.

I noticed that the parabolas created by this pattern, follow this equation per quadrant on the x,y grid.

Where n = 1,2,3,…infinity
Quadrant 1: y = sqrt((2xn)+n^2) = the square root of integer multiples of n

Question, if I use complex numbers, x + iy will I get both quadrants of the parabola? (1&4 for positive n and 2&3 for negative n)

The interesting vector I noticed is at 45 degrees or pi/4 radians.
The sqrt((2xn)+n^2) parabolas intersect that vector at sqrt(((1+sqrt(2))*n)^2).
I have attached an image demonstrating this.

The thing I find most interesting about these intersections is this:

q=((1+sqrt(2))*n)^2
u=((n^2)*6) – q
(q*u)^(1/4) = n

Also interesting side note:

q=((1+sqrt(2))*n)^2
u=((n^2)*12) – 2q
(2q*u)^(1/2) = 2(n^2) = maximum number of electrons an atom's nth electron shell can accommodate

i wonder how it ties into this:
http://vqm.uni-graz.at/pages/qm_gallery/07-pares672e.html
 
  • #101
Raphie said:
Factorials, double factorials (product of odd numbers) and powers of 2 come into play in regards to Volumes of n-balls...

n-ball
http://en.wikipedia.org/wiki/N-sphere#n-ball

And so too Spherical Harmonics...

Hyperspherical volume element
http://en.wikipedia.org/wiki/N-sphere#Hyperspherical_volume_element

So... when summing volumes for a unit sphere, then e will naturally also be involved.

e.g.
pi^e/n! = SUM[V_2n]

Insofar as e relates to the prime number distribution [pi (x) ~ x/ln(x)] specifically, and compound growth generally, that there is some manner of relationship, discovered (and I am unaware of it) or undiscovered, seems evident. The precise nature of this relationship, however, is far less clear.

Keep in mind, however, that the number of conjugacy classes in the Symmetric Group S_n is a partition number:

Conjugacy class
http://en.wikipedia.org/wiki/Conjugacy_class

Since we now know, by the work of Ono et al, that partitions of prime numbers evidence fractal-like behavior, we can also logically surmise that the growth sequences of n-dimensional spaces of dimension p and/or p-1 (and/or p+1) will also be found to exhibit fractal-like behaviors. Think of it this way, and then the root system of a lattice such as E8 (241 is prime, and so too 239...) can, in some manner at least, be thought of as if it were a freeze-framed cross-section of a fractal iterating through multi-dimensional space.

And, insofar as all of this is the case, then Periodicity (e.g. The Crystal Restriction Theorem) and Quasi-periodicity (e.g. Penrose Tilings, related to the Golden Ratio) should also make an appearance is some form. (And so too, for that matter, the Shell theorem that you posted, which has everything to do with theoretical physics...)


RF

As for this...

I need to look more closely at what you've been doing before I can answer.

Raphie, I have a direct link form my equation into Apollonian sphere packing. http://oeis.org/A045506

ex:

5 + 2^2 = 9
7 + 3^2 = 16
11 + 5^2 = 36
13 + 6^2 = 49
17 + 8^2 = 81
19 + 9^2 = 100
23 + 11^2 = 144
...
of course this is linked to the fact that (2^(p-1)-1)/p is congruent to 0 (mod 3), for all primes p greater than 3
...
 
  • #102
Raphie said:
Subtract any two + and - Pentagonal Pyramid numbers of equal index and you get a square. Add them together and you get a cube.

e.g.
40 - 24 = 4^2
40 + 24 = 4^3

One can use this mathematical fact to easily obtain integer solutions to the following:

Period^2 = 4*pi^2/GM * Distance^3 (Kepler's 3rd Law)

e.g.
(40 + 24)^2 = (40 - 24)^3 = 4^6 = 4096
(6 + 2)^2 = (6 - 2)^3 = 2^6 = 64 (= sqrt 4096)

The Pentagonal Pyramid numbers, of course, are the summation of the Pentagonal numbers, which are already well-known to be related to the "timing" and/or "tuning" of the primes.

p^2 - 1 == 1 mod (24) for all p > 3

(p^2 - 1)/24 is Pentagonal for all p > 3.

And, also, as I mentioned previously, 24 s^2 is the Period^2 one obtains if one replaces L/g in the formula for a pendulum with zeta(2)^-2 = (pi^2/6)^-2, where (the reciprocal of) zeta(2) gives the probability of two randomly selected integers being relatively prime.

- RF

Note: Pentagonal Pyramid Numbers have a very easy to remember formula n*T_n = (+) Pentagonal Pyramid # and n*T_-n = (-) Pentagonal Pyramid #, for T_n a Triangular Number.

Also found a direct link to Pentagonal Pyramid numbers while looking for the area or quadrature of the parabolas in my equation.
(n-1)/2 = h (height)
2*sqrt(n)= b (base)
1/2 bh = a (triangle area)

2(a^2) = Pentagonal pyramidal number
 
  • #103
JeremyEbert said:
Also found a direct link to Pentagonal Pyramid numbers while looking for the area or quadrature of the parabolas in my equation.
(n-1)/2 = h (height)
2*sqrt(n)= b (base)
(b*h)/2 = a (triangle area)

2*(a^2) = Pentagonal pyramidal number

also

(n-1)/2 = h
2*sqrt(n)= b
(b*h)/2 = a

2*(a^2) = Pentagonal pyramidal number


if (a*(4/3))^2 is an integer then n is a number having a digital root of 1, 4, 7 or 9.


1, 4, 7, 9, 10, 13, 16, 18, 19, 22, 25, 27, 28, 31, 34, 36, 37, 40, 43, 45, 46, 49, 52, 54...
 
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  • #104
also...
The area of a rectangle A = sqrt(n) * ((n-1)/2) * 4 (this area directly relates to my equation)
When “n” is a square then A/12 = Tetrahedral (or triangular pyramidal) number
Or reducing…
(4n(((n^2)-1)/2)) /12 = Tetrahedral (or triangular pyramidal) number
(n(((n^2)-1)/2)) /3 = Tetrahedral (or triangular pyramidal) number
 
  • #105
JeremyEbert said:
also...
The area of a rectangle A = sqrt(n) * ((n-1)/2) * 4 (this area directly relates to my equation)
When “n” is a square then A/12 = Tetrahedral (or triangular pyramidal) number
Or reducing…
(4n(((n^2)-1)/2)) /12 = Tetrahedral (or triangular pyramidal) number
(n(((n^2)-1)/2)) /3 = Tetrahedral (or triangular pyramidal) number

which directly relates to the Close-packing of spheres:
http://en.wikipedia.org/wiki/Close_packing
 
  • #106
well, since raphie seems to be restricted at the moment, i have to ask, is anyone else following this?
 
  • #107
  • #108
dimension10 said:
Wow, but it is rather a hard method. Is it, by any chance, related to the sieve of erasothones?
dimension10 ,
It is a sieve and all prime sieves seem to smack of Eratosthenes to me. I'm approaching it in my head from a different angle though. My method relates to the fact that a square number added to a prime number only equals another square number when the square added to the prime is equal to ((n-1)/2)^2. Or basically:

n+((n-1)/2)^2 = ((n+1)/2)^2

Its true that all integers share this property despite their primality but composite numbers will have other square congruence, less than the ((n-1)/2)^2 ratio, according to their integer divisors.

These ratios form a lattice when you deal with integers at their square root the way I have. This lattice creates a parabolic coordinate system. This coordinate system is what I'm using to exploit the sieve.

jeremy
* http://en.wikipedia.org/wiki/Congruence_of_squares
* http://en.wikipedia.org/wiki/Parabolic_coordinates
 
  • #109
JeremyEbert said:
Here is a visual prime pattern:
http://plus.maths.org/content/catching-primes
I have developed one of my own based upon trig, square roots and the harmonic sequence.
Here is an animation/application that shows the formula visually:
http://tubeglow.com/test/Fourier.html
Thoughts? Questions?

Ok, maybe I'm the first that doesn't see it. In the first link, I see the primes. In the second link I don't see what identifies the primes. Clue me in.
 
  • #110
PAllen said:
Ok, maybe I'm the first that doesn't see it. In the first link, I see the primes. In the second link I don't see what identifies the primes. Clue me in.

PAllen,
As an intger n increases, the first blue horizontal line north (north/south = y axis) of the green line (east/west = x axis) increases by the square root of n. The intersections of the vertical lines and the concentric circles at the square root of n (blue horizontal line) equate to the divisors d of n by (n-d^2)/2d = 0 mod(.5). Does that help?

Jeremy
 
  • #111
a spherical version of my equation:
http://dl.dropbox.com/u/13155084/PL3D2SPHERE/P_Lattice_3D_Sphere.html
 
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  • #112
Raphie (quoted below),

I'm probably late on this but when saying things like:
(11+13/((1+1)+(1+3)) = 4

You should see what mod9 (*notated by %9) gives you...

I.e.
((x+y)/(x%9+y%9))

It matches most of your numbers...
since mod9 is the infinite digital sum.. (digital sum taken as many times as possible until a single digit is reached)

I.e.
(11+13/((1+1)+(1+3)) == ((11+13)/(11%9+13%9))

Raphie said:
A POSSIBLY RELATED SEQUENCE
Suppose the sum of the digits of prime(n) and prime(n+1) divides prime(n) + prime(n+1). Sequence gives prime(n).
http://oeis.org/A127272
2, 3, 5, 7, 11, 17, 29, 41, 43, 71, 79, 97, 101, 107...

e.g.
(2 + 3)/(2+3) = 1
(3+5)/(3+5) = 1
(5+7)/(5+7) = 1
(7+11)/(7+(1+1)) = 2
(11+13/((1+1)+(1+3)) = 4
(17+19/((1+7)+(1+9)) = 2
(29+31/((2+9)+(3+1)) = 4
(41+43/((4+1) + (4+3)) = 7
(43+47/((4+3)+(4+7)) = 5
(71+73)/((7+1)+(7+3)) = 8
(79+83)/((7+9)+(9+7)) = 5
(97+101)/((9+7)+(1+0+1)) = 11
(101+103)/((1+0+1) + (1+0+3) = 34
(107+109)/((1+0+7)+(1+0+9) = 12

ALSO...
Numbers n such that 1 plus the sum of the first n primes is divisible by n+1.
http://oeis.org/A158682
2, 6, 224, 486, 734, 50046, 142834, 170208, 249654, 316585342, 374788042, 2460457826, 2803329304, 6860334656, 65397031524, 78658228038

002 - 002 = 000 = K_00
012 - 006 = 006 = K_02 (Max)
600 - 224 = 336 = K_10 (Lattice Max known)
924 - 486 = 438 = K_11 (Lattice Max known)

6/(5+1) = 1
42/(6+1) = 6
143100/(224+1) = 636
775304/(486+1) = 1592

Like I said, especially given that these two progressions are ones I came across in the process of writing that last post to you, "hmmmm..."

RELATED PROGRESSIONS
Integer averages of first n noncomposites for some n.
http://oeis.org/A179860
1, 2, 6, 636, 1592, 2574, 292656, 917042, 1108972, 1678508, 3334890730, 3981285760, 28567166356, 32739591796, 83332116034

a(n) is the sum of the first A179859(n) noncomposites.
http://oeis.org/A179861
1, 6, 42, 143100, 775304, 1891890, 14646554832, 130985694070, 188757015148, 419047914740, 1055777525624570390, 1492138298614167680, 70288308055831268412, 91779857115464381780, 571686203669195590338

Numbers n that divide the sum of the first n noncomposites.
http://oeis.org/A179859
1, 3, 7, 225, 487, 735, 50047, 142835, 170209, 249655, 316585343, 374788043, 2460457827, 2803329305, 6860334657

This number, in particular, I find interesting...
142835 = 5*7^2*11*53 = (142857 - par_8) = (142857 - 22)
vs. 1/7 = .142857 (repeating)
Indexing from 0, 142857 is the 24th Kaprekar Number

1, 3, 7 and 225, the 1st 4 terms in that last sequence above == (2^1 - 1)^1, (2^2 - 1)^1, (2^3 - 1)^1, (2^4 - 1)^2.

- RF
 
  • #113
update:
http://dl.dropbox.com/u/13155084/prime.png
 
Last edited by a moderator:

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