Am I overthinking this problem? A 15uF capacitor is connected ot a 55V battery and becomes fully charged. The battery is removed and the circuit is left open. A slab of dielectric material is inserted to completely fill the space between the plates. It has a dielectric constant of 4.8. What is the voltage across the capacitor plates after the slab is in place? I'm thinking that I just use V = Vo/k = 55/4.8 =11.5V This seems too easy and doesn't use the value for the capacitor. Can anyone tell me if I'm totally off in my thinking?