Superwoman was seen packing up a suspicious bundle into a wagon, which has a total mass of 25.0 kg and is at rest. She pulls the wagon towards the east with an applied force of 60.0 N, which makes an angle of 35.0° above the horizontal. The coefficient of friction is 0.100 between the wagon wheel and the ground. a) Draw and label a free body diagram. b) Calculate the acceleration of the wagon. c) If the acceleration remains constant, what will the final velocity of the wagon be when t = 7.0s? d) If the work done by air resistance is 15J, determine the final velocity of the wagon when t=7.0s. e) What is the wagon's displacement when t=7.0s? So I drew a FBD. And found that a=1.12 m/s^2 (by finding Fnormal using Fnety = Fnormal + Fapplied - Fgravity = 0 and then using Fnormal in Fnetx = Fapplied*cos35 - Ffriction. Then Fnetx = ma) c) V=Vo +at t = 7.0s Vo = 0 a = 1.12 Therefore V = 7.9 m/s d) ?? Here's the answer the teacher gave me, but I don't understand it: 1/2mv^2 -15 = 1/2mv2^2 1/2(25)(7.9)^2 -15 = 1/2(25)(V2^2) 765.125 = 1/2(25)(V2^2) V2 = 7.82 m/s [E] I don't get why the air resistance is subtracted from Work done at t=7.0s. Please help explain part d to me...thank you!