What is the Work and Friction in This Incline Scenario?

  • Thread starter Thread starter marker403
  • Start date Start date
  • Tags Tags
    Friction Work
Click For Summary
SUMMARY

The discussion centers on calculating work and friction in a physics problem involving a 93N crate pushed 10m up a 37-degree incline with a constant velocity. The worker exerts an 85N force parallel to the incline, resulting in 850 joules of work done by the worker. The work done by gravity is calculated as 560 joules. The forum participants seek assistance in determining the work done by friction and the coefficient of friction, utilizing the relationship between non-conservative forces and energy change.

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Familiarity with the concept of work in physics
  • Knowledge of gravitational force calculations
  • Basic principles of friction and normal force
NEXT STEPS
  • Calculate the work done by friction using the formula W = F x d
  • Determine the coefficient of friction using Ff = (u)(Fn)
  • Explore the concept of non-conservative forces and their impact on energy
  • Review the calculation of normal force on an incline
USEFUL FOR

Students studying physics, particularly those focusing on mechanics, as well as educators seeking to clarify concepts related to work, friction, and forces on inclined planes.

marker403
Messages
3
Reaction score
0

Homework Statement



A worker pushes a 93N crate 10m up a 37 degree incline with constant velocity. The worker exerts a force of 85N parallel to the incline.

a. How much work does he do?
b. How much work is done by gravity?
c. How much work is done by friction?
d. What is the coefficient of friction between the box and the incline?

Homework Equations



Work = Force x Distance
Ff = (u)(Fn)

The Attempt at a Solution



Part A:

work = (85 N)(10 m) = 850 joules

Part B:

work = (10 * sin(37)) * 93 N = 560 N

I believe these are correct. The parts that I do not know how to do are C and D. Anyone know how? I greatly appreciate all help :)
 
Physics news on Phys.org
HINT:

The net work done by non conservative forces (i.e. the force of the push and friction) will equal the negative of the change in energy of the box:

[tex]W_{non-conservative}=-\Delta E[/tex]

Can you use this to find the answers for parts C and D?
 
Thank you for your help!

So the force of friction is -850 joules?

For Part D, I am supposed to use the friction force for Ff and the normal force for Fn, right?

Is the normal force 93 N?
 
Last edited:

Similar threads

  • · Replies 7 ·
Replies
7
Views
8K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 8 ·
Replies
8
Views
2K
Replies
18
Views
3K
Replies
29
Views
3K
Replies
8
Views
3K
Replies
4
Views
3K
  • · Replies 33 ·
2
Replies
33
Views
4K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 11 ·
Replies
11
Views
5K