What is the Work Done on a Carton on an Inclined Ramp?

[SuPaFly43218]

Homework Statement

A 128 N carton is pulled up a frictionless baggage ramp inclined at 30.0 degrees above the horizontal by a rope exerting a 72.0 N pull parallel to the ramp's surface. If the carton travels 5.20 m along the surface of the ramp, calculate the work done on it by the rope, gravity, and the normal force of the ramp.

Homework Equations

W= force*cos(theta)* displacement

The Attempt at a Solution

Work done on carton by ROPE W=72cos(30)*5.2 Answer comes out to 324 J, which is wrong.

Work done on carton by GRAVITY W=128cos(30)*5.2 Answer comes out to 576 J, which is wrong...

What am I getting incorrect about this?

 

[SuPaFly43218]

Well, i figured out the work done on the carton by the rope because the angle of the rope is NOT 30 degrees, it is parallel, thus 0degrees. Still can't figure out the gravity one though..

 

[heth]

Homework Equations

W= force*cos(theta)* displacement

Did you start with a sketch showing all of the forces acting on the object, along with the ramp and the angle theta?

Where did you get this equation from? What do the variables in it represent? Is the equation relevant here?

 

[SuPaFly43218]

NVM, figured them all out!