What is your acceleration towards the end of the cliff?

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SUMMARY

The discussion revolves around calculating the acceleration of a 100kg individual holding a vine connected to a 50kg friend hanging over a cliff. The net forces acting on both individuals are analyzed using Newton's second law (Fnet = ma). The forces include gravitational force (Fg) and tension in the vine (Ft). The conclusion emphasizes the importance of drawing free body diagrams to visualize forces and apply Newton's laws effectively to solve for the unknown tension and acceleration.

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  • Understanding of Newton's second law (Fnet = ma)
  • Knowledge of free body diagrams and force analysis
  • Familiarity with gravitational force calculations (Fg = mg)
  • Basic algebra for rearranging equations and solving for unknowns
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  • Study free body diagram techniques for complex systems
  • Learn about tension in ropes and its applications in physics
  • Explore advanced applications of Newton's laws in multi-body systems
  • Investigate the effects of frictionless surfaces on motion dynamics
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Physics students, educators, and anyone interested in understanding dynamics and force interactions in systems involving multiple bodies and tension forces.

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1.
You having a mass of 100kg hold one end of an ideal vine (infinitely strong, completely flexible, but having zero mass). The vine runs horizontally to the edge of a cliff, then vertically to where your friend (mass 50kg) is hanging on, above a pack of hungry Velociraptors. A sudden sleet storm has removed all friction, assuming that you can hang on, what is your acceleration towards the end of the cliff?

2.
Fnet=ma
Fnet1=Fg1 - Ft
Fnet2=Fg2 - Fn + Ft


3. I drew the picture and tried to rearrange equations and use substitution, but had troubles and can't get a reasonable answer. i know 100kg person has Fg2 of 980N down and Fn of 980N up. the 50kg person has a Fg1 of 490N down, but i can't get the Force of tension in the rope (Ft)
 
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Draw free body diagrams of each person and note the forces acting on each. You have identified correctly the forces on the 50 kg person (his weight down, and unknown tension force up), which is the net force, and which must be equal to 50a.
For the other person, you need not look in the vertical direction, just consider the forces acting on her in the x direction.. What are they? Then use Newton 2 for that person also. Then continue...
 

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