- #1

aaronfue

- 122

- 0

## Homework Statement

The motorcyclist attempts to jump over a series of cars and trucks and lands smoothly on the other ramp, i.e., such that his velocity is tangent to the ramp at B. Determine the launch speed v

_{A}necessary to make the jump.

Image attached.

## Homework Equations

a = -9.81 [itex]\frac{m}{s^2}[/itex]

x

_{B}= x

_{o}+ (v

_{o})

_{x}t + [itex]\frac{1}{2}[/itex]at

^{2}

y

_{B}= y

_{o}+ (v

_{o})

_{y}t + [itex]\frac{1}{2}[/itex]at

^{2}

## The Attempt at a Solution

I set my point of origin for my coordinate system right at point A (end of ramp). I wanted to keep from using the 3 m height of both ramps. (Would I be able to solve this problem this way?)

I came up with the following equations:

Equation 1 (vertical motion): v

_{A}sin30 - [itex]\frac{9.81}{2}[/itex]t

^{2}= 0

Equation 2 (horizontal motion): v

_{A}cos30t = 25

Is this the correct approach? Are there any errors?