What Medium Does Light Travel Through in Space?

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Sagittarius A-Star said:
The EM-wave function follows from Maxwells equations.
Derivation of the EM wave function (a linear, second-order partial differential equation) from Maxwells equations in (3+1) notation, Gaussian CGS units (see posting #107)

Write the ##curl## of Faradays law:
## \nabla \times (\nabla \times \mathbf{E}) = \nabla \times \left( - \frac{\partial \mathbf{B}}{\partial (ct)} \right)##
Apply the vector identity ##\nabla \times (\nabla \times \mathbf{A}) = \nabla(\nabla \cdot \mathbf{A}) - \nabla^2 \mathbf{A}## on the LHS and switch order of partial and time derivatives on the RHS:
##\nabla(\nabla \cdot \mathbf{E}) - \nabla^2 \mathbf{E} = -\frac{\partial}{\partial (ct)} (\nabla \times \mathbf{B})##
Substitute Gauss's law (##\nabla \cdot \mathbf{E} = 0##) and Ampere's law for (##\nabla \times \mathbf{B}##):
$$\nabla^2 \mathbf{E} - \frac{1}{c^2} \frac{\partial^2 \mathbf{E}}{\partial t^2} = 0$$
 
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