What net force is acting on the object along the incline?

[rculley1970]

Problem:

An object of mass 2.0kg starts from rest and slides down an inclined plane 69cm long in 0.90s. What net force is acting on the object along the incline?


Now, I used what I was given and plugged it in the equation:

deltaX=1/2at^2 + V0t

I come up with acceleration = .0552 m/s^2

I plug this into equation:

Fnet = ma for a net force of .11N

This is wrong. Am I missing something? I don't have angle theta to use the equation: mgsin(theta).

 

[d_leet]

Problem:

An object of mass 2.0kg starts from rest and slides down an inclined plane 69cm long in 0.90s. What net force is acting on the object along the incline?


Now, I used what I was given and plugged it in the equation:

deltaX=1/2at^2 + V0t

I come up with acceleration = .0552 m/s^2

I plug this into equation:

Fnet = ma for a net force of .11N

This is wrong. Am I missing something? I don't have angle theta to use the equation: mgsin(theta).

What did you do to get that for an acceleration, that's not what I get when I use your equation.

 

[Lisa...]

Now, I used what I was given and plugged it in the equation:

deltaX=1/2at^2 + V0t

I come up with acceleration = .0552 m/s^2

Your thinking is correct, the only thing is that the acceleration you've calculated isn't the correct value.

The problem indicates that:

x= 69 cm = 69 * 10^-2 m
v0= 0 m/s
t= 0.90 s

Because v0= 0 m/s the equation deltaX=1/2at^2 + V0t becomes:

deltaX=1/2at^2

therefore

2 delta X= at² so
a= 2 delta X/ t²

Can you get to the right answer now?

 

[rculley1970]

oops, i messed up the easy algebra and put .5t^2 on the denominator instead of multiplying deltaX by two. Such an easy mistake can kill a problem. Thanks for everyones help.