What points is the tangent line of curve paralell to a vector?

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SUMMARY

The discussion centers on finding points on the curve defined by the equation 4x² - xy + y² = 4 where the tangent line is parallel to the vector [1, 1]ᵀ. Participants confirm that the vector [1, 1] indicates the direction of the tangent line. The solution involves using implicit differentiation to derive dy/dx, substituting the slope corresponding to the vector, and solving for the specific points on the curve.

PREREQUISITES
  • Understanding of implicit differentiation
  • Familiarity with gradient vectors
  • Knowledge of tangent lines in calculus
  • Basic algebraic manipulation skills
NEXT STEPS
  • Practice implicit differentiation with various equations
  • Study the concept of gradient vectors and their applications
  • Explore the relationship between tangent lines and slopes
  • Learn how to solve for points of tangency on curves
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Students studying calculus, particularly those focusing on implicit differentiation and tangent line concepts, as well as educators looking for examples of vector applications in calculus.

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Homework Statement


4x^2 - xy + y^2 = 4
At what points is the tangent line to the above curve vector [1 1]T? (T means I transposed the vector)


Homework Equations





The Attempt at a Solution


I have the gradient vector, but I'm conceptually lost about what to do after that.
 
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How can the tangent line be a vector? Do you mean that the vector (1,1) is parallel to the tangent line? If so, just use implicit differentiation, substitute the appropriate value for dy/dx, and solve.
 

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