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At what point does the curve y=e^(32x) have maximum curvature?

I have tried this method: http://www.math.washington.edu/~conroy/m126-general/exams/mt2SolMath126Win2006.pdf

Problem 4. Adapting for 32x rather than x

it seems to get a bit lengthier with 32x than with x

i got ( -log(2048)/64, 1/32sqrt(2) )

but this was incorrect .

It seems finding the critical number takes some manipulations.

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# @what pt. does y=e^(32x) have max curvature?

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