What Reactions Occur in a Battery with Two Half Cells?

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SUMMARY

The discussion centers on the electrochemical reactions occurring in a battery consisting of two half cells: a silver rod in a 100 mL AgNO3 0.025 M solution and a zinc rod in a 100 mL Zn(NO3)2 0.150 M solution. The oxidation reaction at the zinc electrode is represented as Zn(s) → Zn2+(aq) + 2e-, while the reduction reaction at the silver electrode is Ag+(aq) + e- → Ag(s). The net reaction combines these half-reactions, demonstrating that zinc acts as the anode (oxidation) and silver as the cathode (reduction), facilitating electron flow and electricity generation.

PREREQUISITES
  • Understanding of redox reactions and their components
  • Familiarity with electrochemical cells and half-cell reactions
  • Knowledge of ionic equations and state symbols
  • Basic principles of oxidation and reduction (LEO says GER)
NEXT STEPS
  • Study the Nernst equation for calculating cell potential
  • Explore the concept of salt bridges in electrochemical cells
  • Learn about different types of electrochemical cells, including galvanic and electrolytic cells
  • Investigate the role of concentration in electrochemical reactions, particularly using the Nernst equation
USEFUL FOR

Chemistry students, educators, and anyone interested in understanding electrochemical processes and battery technology.

lonerider
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Homework Statement


I have got a battery with two half cells.

One cell with.
A silver rod in a 100 mL AgNO3 0,025 M solution.

One cell with.
A zinc rod in a 100 mL Zn(NO3)2 0,150 M solution.

So my question is what reactions happen?

And which reaction is the electricity providing one?

Homework Equations


I do not think that there are any

The Attempt at a Solution


My bet

First cell (with Ag)
Ag+ + NO3- + e- -> Ag + NO3-

Second cell (with Zn)
Zn(NO3)2 -> Zn2+ NO32- but then where are the electrons? Furthermore I think this is the electricity providing one!
 
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Not to be irritating, but some help would be very appreciated...
 
Homemade batteries are cool to make. This info doesn't really help you but you should also try yo make a http://sci-toys.com/scitoys/scitoys/echem/fuel_cell/fuel_cell.html" . Its pretty interesting.
 
Last edited by a moderator:
Well I am afraid (as you said) that piece of information will not prove very usefull...
 
First off, you need to label solids, aqueous or gaseous of the elements & solutions.

Basic idea: Redox Reactions [reduction & oxidation reactions. LEO says GER, Loss of Electrons = Oxidation. GER = Gain of Electrons = Reduction. You basically have a reaction where there's a loss of electrons and a gain of electrons.

To cause the loss or gain of these electrons there needs to be reactions taking place that turns these elements into ions.

Here's some things to think about

Ag solid silver rod -> What does it want to be and what does it do?
Zn solid silver rod -> What does it want to be and what does it do?

Ag Solution -> What is this exactly [*note* you figure out it's charge]?
Zn Solution -> What is this exactly [*note* you figure out it's charge]?

How is AgNO3 and Zn(NO3)2 related to both?

Have a try at the problem again and if not, I'll help you through it.
 
Last edited:
lonerider said:

Homework Statement


I have got a battery with two half cells.

One cell with.
A silver rod in a 100 mL AgNO3 0,025 M solution.

One cell with.
A zinc rod in a 100 mL Zn(NO3)2 0,150 M solution.

So my question is what reactions happen?

And which reaction is the electricity providing one?

Homework Equations


I do not think that there are any

The Attempt at a Solution


My bet

First cell (with Ag)
Ag+ + NO3- + e- -> Ag + NO3-

Second cell (with Zn)
Zn(NO3)2 -> Zn2+ NO32- but then where are the electrons? Furthermore I think this is the electricity providing one!

In the first equation, you have written Ag+ and NO3- as ions, whereas in the second you have written Zinc Nitrate as a compound. You should stick to writing out the ionic equations.

Also, in the second equation, you have the charge on the nitrate ion as 2-; this is different to the (correct) ion in the first equation.

You also seem to be mixing up metal solids and metal ions. Try using state symbols. Do you know how Ag(s) is different to Ag2+(aq)? Try writing the equations again.

edit: very slow typing from me!
 
AngeloG said:
First off, you need to label solids, aqueous or gaseous of the elements & solutions.

Basic idea: Redox Reactions [reduction & oxidation reactions. LEO says GER, Loss of Electrons = Oxidation. GER = Gain of Electrons = Reduction. You basically have a reaction where there's a loss of electrons and a gain of electrons.

To cause the loss or gain of these electrons there needs to be reactions taking place that turns these elements into ions.

Here's some things to think about

Ag solid silver rod -> What does it want to be and what does it do?
Zn solid silver rod -> What does it want to be and what does it do?

Ag Solution -> What is this exactly [*note* you figure out it's charge]?
Zn Solution -> What is this exactly [*note* you figure out it's charge]?

How is AgNO3 and Zn(NO3)2 related to both?

Have a try at the problem again and if not, I'll help you through it.

Well the main problem is that I know I have to solutions.

Ag(s)+Ag+(aq)+NO3-(aq) ->

I have no idea what that will become the same about the zinc where it is.


Zn(s)+Zn2+(aq)+2NO3-(aq) ->

That is kind of where I am stuck...
 
Here's a thought: Does the NO3 matter as an ion or a compound? Will it cancel itself out in the end equation?

Zn ( s ) -> Zn 2+ ( aq ) + 2 e-
Ag ( s ) -> Ag + ( a ) + 1 e-

What happens with the net reaction?
 
Well but then what really happens if you put that together you get that
Zn ( s ) 2Ag(aq)+ -> Zn 2+ ( aq ) + 2Ag(s)
 
  • #10
That is exactly what happens during the reaction.

Now tell me. Which one is the anode and which one is the cathode?

I'll take you through the steps through each post heh.

Remember, LEO says GER. Anode = oxidation occurs, Cathode = reduction occurs.

Just a side note->
Normally, in a cell reaction there is a salt bridge. In which electrons can flow freely between both cells heh.

I have my college class in about 15 minutes [2 PM PST -> 3:20 PM PST]; so if I don't get to you that's the reason why.
 
  • #11
Well thank you you have helped enough, you have been very heplful and for that I am most grateful. Thanks a lot!
 

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