What Shape Do the Characteristic Curves of This PDE Form?

Join the discussion
Registration is free. Start your own thread to ask a follow-up.
1 reply · 2K views
jimmycricket
Messages
115
Reaction score
2

Homework Statement


suppose [tex]u(x,y)[/tex] satisfies the partial differential equation:
[tex]-4y\frac{\partial u}{\partial x}+\frac{\partial u}{\partial y}=0[/tex]
Find the characteristic curves for this equation and name the shape they form

The Attempt at a Solution


[tex]\frac{dy}{dt}=1 \Longrightarrow y=t+y_0[/tex]
[tex]\frac{dx}{dt}=-4y=-4(t+y_0) \Longrightarrow x=-2t^2-4y_0t+x_0[/tex]

What can I say about the shape these curves form?
 
Physics news on Phys.org
jimmycricket said:

Homework Statement


suppose [tex]u(x,y)[/tex] satisfies the partial differential equation:
[tex]-4y\frac{\partial u}{\partial x}+\frac{\partial u}{\partial y}=0[/tex]
Find the characteristic curves for this equation and name the shape they form



The Attempt at a Solution


[tex]\frac{dy}{dt}=1 \Longrightarrow y=t+y_0[/tex]
[tex]\frac{dx}{dt}=-4y=-4(t+y_0) \Longrightarrow x=-2t^2-4y_0t+x_0[/tex]

What can I say about the shape these curves form?

[itex]y[/itex] is a first-order polynomial in [itex]t[/itex]. [itex]x[/itex] is a quadratic in [itex]t[/itex]. Therefore [itex]x[/itex] is a quadratic in [itex]y[/itex]. What shape does the graph of a quadratic function have?