What Speed and Angle Does m2 Leave After Collision?

[texan14]

Homework Statement

A mass "m₁" moves along the x-axis with velocity of magnitude v₀ on a frictionless table. It strikes another mass m₂ which is initially at rest. The mass m₁ goes off along the y-axis. If half the original kinetic energy is lost in the collision, with what speed and at what angle does m₂ leave the point of collision?

Homework Equations

1/2KE(initial) = KE(final)
(1/2)P_ix=P_fx
(1/2)P_iy=P_fy

The Attempt at a Solution

P_ix=v_om₁
P_fx=u₂m₂cosθ
P_iy=0
P_fy=u₁m₁ - u₂m₂sinθ

I think these are the initial and final components of momentum, but I don't know how to find θ and u₂ in terms of known variables.

 

[tiny-tim]

hi texan14!

1/2KE(initial) = KE(final)
(1/2)P_ix=P_fx
(1/2)P_iy=P_fy
…
P_ix=v_om₁
P_fx=u₂m₂cosθ
P_iy=0
P_fy=u₁m₁ - u₂m₂sinθ

you seem to be confusing KE and momentum

what is your KE equation?​