(adsbygoogle = window.adsbygoogle || []).push({});

The drawing shows a collision between two pucks on an air-hockey table. Puck A has a mass of 0.0480 kg and is moving along the x axis with a velocity of +7.76 m/s. It makes a collision with puck B, which has a mass of 0.0960 kg and is initially at rest. The collision is not head-on. After the collision, the two pucks fly apart with the angles shown in the drawing. Find the speed of (a) puck A and (b) puck B.

There are no answers provided. Could someone please tell me if my answers are correct?

Momentum in the y direction

Piy = Pfy

0 = MaVasin65 + -MbVbsin37

MaVasin65 = MbVbsin37

Va = MbVbsin37 / Ma*sin65

Va = (0.096sin37Vb) / (0.048sin65)

Pix = Pfx

0.048(7.76) = 0.048cos65Va + 0.096cos37Vb

Plug Va in and you get Vb = 3.595 m/s and thus Va = 4.77 m/s ?

**Physics Forums - The Fusion of Science and Community**

# Hockey puck momentum, conservation of linear momentum

Know someone interested in this topic? Share a link to this question via email,
Google+,
Twitter, or
Facebook

- Similar discussions for: Hockey puck momentum, conservation of linear momentum

Loading...

**Physics Forums - The Fusion of Science and Community**