Hockey puck momentum, conservation of linear momentum

  1. ch07p_30.gif

    The drawing shows a collision between two pucks on an air-hockey table. Puck A has a mass of 0.0480 kg and is moving along the x axis with a velocity of +7.76 m/s. It makes a collision with puck B, which has a mass of 0.0960 kg and is initially at rest. The collision is not head-on. After the collision, the two pucks fly apart with the angles shown in the drawing. Find the speed of (a) puck A and (b) puck B.

    There are no answers provided. Could someone please tell me if my answers are correct?

    Momentum in the y direction
    Piy = Pfy
    0 = MaVasin65 + -MbVbsin37
    MaVasin65 = MbVbsin37
    Va = MbVbsin37 / Ma*sin65
    Va = (0.096sin37Vb) / (0.048sin65)

    Pix = Pfx
    0.048(7.76) = 0.048cos65Va + 0.096cos37Vb

    Plug Va in and you get Vb = 3.595 m/s and thus Va = 4.77 m/s ?
    Last edited: Oct 14, 2011
  2. jcsd
  3. Yes.
Know someone interested in this topic? Share this thead via email, Google+, Twitter, or Facebook

Have something to add?