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## Homework Statement

A 0.800 kg target slides along the ice at 3.0 m/s [W], when it is hit by a 20.0 g arrow moving at 260 m/s [N], as part of a show. Find the final velocity of the target after the inelastic collision.

## Homework Equations

pi= pf

m1 v1i+ m2 v2i = (m1+ m2)vf

pythagorean theorem

## The Attempt at a Solution

v1f= ?

pix= pfx

m1 v1ix+ m2 v_2ix = (m1+ m2)vfx

(0.80)(-3.0)+0=(0.80+0.020) vfx

-2.4=(0.820)vfx

v_fx= -2.93 m/s

piy= pfy

m1 v1iy+ m2 v2iy = (m1+ m2)vfy

0+(0.02)(260)=(0.800+0.02) vfy

vfy=5.2/0.82=6.34 m/s

vf=√(-2.93)^2+(6.34)^2

vf=6.98 m/s

tanθ= -2.93/6.34

θ=25°

Since one of these values are negative, the angle is negative. Relatively speaking what would the angle be. also was this question in general answered correctly?